Which expression is equivalent to 2^4 ⋅ 2^−7?

2 answers:

8 0

Remember
$(x^m)(x^n)=x^{m+n}$
and
$x^{-m}=\frac{1}{x^m}$

so
$(2^4)(2^{-7})=$
$2^{4-7}=$
$2^{-3}=$
$\frac{1}{2^3}=$
$\frac{1}{8}$

ivanzaharov [21]3 years ago

5 0

Answer:

The answer is 1 over 2^3

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .