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tino4ka555 [31]
1 year ago
12

What is the area, measured in square centimeters, of the green shape

Mathematics
1 answer:
DaniilM [7]1 year ago
7 0

Answer:

14

Step-by-step explanation

Count the whole squares and you get 12. Then count the triangles and you have four. Two triangles = 1 square so you have two squares. After add two and 12.

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on three days last week maria ran 3/4 mile 7/8 mile and 3/5 mile. List the distances in order from least to greatest
Dafna11 [192]
3/5 3/4 7/8
As the higher the denominator and the higher the numerator or 'parts filled', the greater the fraction.
4 0
3 years ago
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Kevin drew a triangle with angle measures of 30 degrees and 40 degrees and side measures of 5 cm, 7cm, and 8 cm. Explain, using
Pavel [41]

Answer:  

He drew a scalene triangle

Step-by-step explanation:

A scalene triangle is where all side measure and all angle measure are different.

8 0
2 years ago
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The product of 7/8 and 9/10 is greater then 9/10
kati45 [8]
No the product will be less than 9/10.
This can be easily seen if the fractions are converted into decimals.
The decimal form of the product of 7/8 and 9/10 is 0.867 while the decimal form of 9/10 is 0.9. Therefore, the product of 7/8 and 9/10 is not greater than 9/10
3 0
3 years ago
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What is the square root of <br> X of the power of 2 -1 =80?
zepelin [54]

Answer:

x=6561

Step-by-step explanation:

We can solve this equation for x to get

\sqrt{x} -1=80\\\\\sqrt{x} =81\\x=(81)^2\\\\x=6561

5 0
3 years ago
The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

174.5 ± 2.334* \frac{6.9}{\sqrt{50} }

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

4 0
2 years ago
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