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Vsevolod [243]
3 years ago
6

What is 1/3÷1/2 math answers?

Mathematics
2 answers:
Natali5045456 [20]3 years ago
5 0

Answer:

Step-by-step explanation:

1/3 * 2/1 = 2/3

Sergeeva-Olga [200]3 years ago
5 0

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

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To train for a race, Scott wants to run 20 miles this week. He runs 14
mestny [16]

Answer:

3 mile

Step-by-step explanation:

total miles= Monday+Tuesday+x

20=14+3+x

20=17+x

-17  -17

__________

3=x

Scott needs to run 3 more miles

Hope this helps!

5 0
3 years ago
Show that each property of matrices is true for all 2 by 2 matrices scalar distributive
OLga [1]
I don't know either. sorry.
8 0
3 years ago
Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8
Delvig [45]
We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34
Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86

Thus the 98% confidence interval will be (105.34, 141.86)


Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.
3 0
3 years ago
It is recommended that adults consume at least 1,000 mg of calcium every day. One ounce of whole milk contains about 25 mg of ca
Maksim231197 [3]

Answer:

A= 50oz milk + 2 oz cheese

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Answer for x -4x-1=3
nordsb [41]

Answer:

4 x 1 = 4 x 3 = 12 = 4 x 3

Step-by-step explanation:

sorry I'm having trouble with this too

7 0
3 years ago
Read 2 more answers
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