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3 years ago

I need help please i struggle on these questions

Mathematics

1 answer:

-Dominant- [34]3 years ago

7 0

Answer:

1. AB is a diameter. (False)

2. ST, SP and SQ are radii. (True)

3. SQ = 12 cm. (False)

4. PQ is 12 cm. (True)

Step-by-step explanation:

1. AB is not a diameter because a diameter must pass through the center of the circle.

2. ST, SP and SQ are radii because they all meet at the center of the circle.

3. SQ is not equal to 12 cm. SQ is equal to 6 cm because it is a radius.

4. PQ is equal to 12 cm because it is a diameter. Radius = 6 cm. Diameter = 2 × radius = 2 × 6 cm = 12 cm

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3 years ago

Find the area of a regular hexagon with a radius of 6 in

s344n2d4d5 [400]

Hexagon is a total of 6 triangle
Let find area of one triangle the multiplying with 6
Area of a triangle is A=1/2bh
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3 years ago

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bogdanovich [222]

Answer:

<h2><em>Three to the three fifths power.</em></h2>

Step-by-step explanation:

The given expression is

$\sqrt{3\sqrt[5]{3} }$

To simplify this expression, we have to use a specific power property which allow us to transform a root into a power with a fractional exponent, the property states:

$\sqrt[n]{x^{m}}=x^{\frac{m}{n}}$

Applying the property, we have:

$\sqrt{3\sqrt[5]{3}}=\sqrt{3(3)^{\frac{1}{5}}}=(3(3)^{\frac{1}{5}})^{\frac{1}{2}}$

Now, we multiply exponents:

$(3(3)^{\frac{1}{5}})^{\frac{1}{2}}\\3^{\frac{1}{2}}3^{\frac{1}{10}}$

Then, we sum exponents to get the simplest form:

$3^{\frac{1}{2}}3^{\frac{1}{10}}=3^{\frac{1}{2}+\frac{1}{10}} =3^{\frac{10+2}{20}}=3^{\frac{12}{20}} \\\therefore \sqrt{3\sqrt[5]{3}}=3^{\frac{3}{5} }$

Therefore, the right answer is <em>three to the three fifths power.</em>

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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