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2 years ago

Select the three subjects studied in sports biomechanics.

Computers and Technology

1 answer:

swat322 years ago

8 0

Answer:

physics

human anatomy

physiology

Explanation:

physics, human anatomy, physiology, functional anatomy, engineering, and exercise science.

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Outside of a C program, a file is identified by its ________while inside a C program, a file is identified by a(n) ________. fil

Alexxandr [17]

Answer: name, file stream object

Explanation:

4 0

2 years ago

Which of the following does not make a good analysis class? (Points : 6) its name reflects its intent

satela [25.4K]

Answer:it has high coupling

Explanation: Coupling is the property in the field of computer program that is defined as the functions ,data and codes of the program are dependent on each other and cannot be changed independently if requires. Thus,high amount of coupling is not considered as good factor due to high interdependence. Loose coupling can be still permitted.

Other options are correct because name of the class should reflect the purpose and well defined responsibilities should be present, modeling of certain component and high cohesion means keeping similar functions togather is also required. So, the only bad factor is high coupling

6 0

2 years ago

When was Microsoft released to public schools?

Studentka2010 [4]

April 4
1975...$.$.$.........&.$.$.$....................

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3 years ago

Write a program that takes in a line of text as input, and outputs that line of text in reverse. The program repeats, ending whe

Nana76 [90]

Answer:

using System;

public class Program

{

public static void Main()

{

String input ;

while(true)

{

input = Console.ReadLine();

if(input.Equals(""quit""))

break;

Reverse_String(input);

}

return;

}

static void Reverse_String(string input_text)

{

char[] text = input_text.ToCharArray();

Array.Reverse(text);

Console.WriteLine(text);

}

Explanation:

In the above program a separate function is written to reverse the string.

This method takes the string as an argument and place it in a array and then use the built-in function reverse and print the reversed string in the console.

In the main(), the input is obtained from the console and it is passed to the reversestring(). 

7 0

2 years ago

Read 2 more answers

1. How many bits would you need to address a 2M × 32 memory if:

Dominik [7]

Answer:

a) 23 b) 21
a) 43 b) 42
a) 0 b) 0

Explanation:

1) How many bits is needed to address a 2M * 32 memory

2M = 2^1*2^20, while item =32 bit long word

hence ; L = 2^21 ; w = 32

a) when the memory is byte addressable

w = 8; L = ( 2M * 32 ) / 8 = 2M * 4

hence number of bits = log2(2M * 4)= log2 ( 2 * 2^20 * 2^2 ) = 23 bits

b) when the memory is word addressable

W = 32 ; L = ( 2M * 32 )/ 32 = 2M

hence the number of bits = log2 ( 2M ) = Log2 (2 * 2^20 ) = 21 bits

2) How many bits are required to address a 4M × 16 main memory

4M = 4^1*4^20 while item = 16 bit long word

hence L ( length ) = 4^21 ; w = 16

a) when the memory is byte addressable

w = 8 ; L = ( 4M * 16 ) / 8 = 4M * 2

hence number of bits = log 2 ( 4M * 2 ) = log 2 ( 4^1*4^20*2^1 ) ≈ 43 bits

b) when the memory is word addressable

w = 16 ; L = ( 4M * 16 ) / 16 = 4M

hence number of bits = log 2 ( 4M ) = log2 ( 4^1*4^20 ) ≈ 42 bits

3) How many bits are required to address a 1M * 8 main memory

1M = 1^1 * 1^20 , item = 8

L = 1^21 ; w = 8

a) when the memory is byte addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

hence number of bits = log 2 ( 1M ) = log2 ( 1^1 * 1^20 ) = 0 bit

b) when memory is word addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

number of bits = 0

5 0

2 years ago