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Answer:
public class Main
{
public static void main(String[] args) {
System.out.println(min(3, -2, 7));
}
public static int min(int n1, int n2, int n3){
int smallest = Math.min(Math.min(n1, n2), n3);
return smallest;
}
}
Explanation:
*The code is in Java.
Create a method named min that takes three parameters, n1, n2, and n3
Inside the method:
Call the method Math.min() to find the smallest among n1 and n2. Then, pass the result of this method to Math.min() again with n3 to find the min among three of them and return it. Note that Math.min() returns the smallest number among two parameters.
In the main:
Call the method with parameters given in the example and print the result
Answer:
#include <iostream>
#include <time.h>
#include <string>
using namespace std;
int main(){
srand(time(NULL));
cout<<"Throw dice"<<endl;
int b =0;
int a=0;
a=rand()%6;
b=rand()%6;
for (int i =0;i<1;i++)
{cout<<"dice one: "<<a<<endl;}
for (int i =0;i<1;i++)
{cout<<"dice two: "<<b<<endl;}
if(a>b)
{cout<<"first dice won"<<endl;}
if(b>a)
{cout<<"second dice won"<<endl;}
else{cout<<"they are same"<<endl;
return main();
}
return 0;
}
Explanation:
/*maybe it help you it is almost done*/
Answer:
Bandwidth describes the maximum data transfer rate of a network or Internet connection. ... For example, a gigabit Ethernet connection has a bandwidth of 1,000 Mbps (125 megabytes per second). An Internet connection via cable modem may provide 25 Mbps of bandwidth.
