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2 years ago

What is the product of 9200 and 2.3 x 10^3 expressed in scientific notation

Mathematics

1 answer:

Damm [24]2 years ago

8 0

Answer:

21.16 x 10^6 or 2.116 x 10^7

Step-by-step explanation:

First, rewrite 9200 in scientific notation. This can be expressed as 9.2 x 10^3.

Now you can multiply and add the exponents.

9.2 x 2.3 = 21.16

3 + 3 = 6

21.16 x 10^6 or 2.116 x 10^7

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Mario claims that a Rhombus is sometimes a square, but a square is always a rhombus. Is he correct? Explain your answer

KIM [24]

No, I know this because a square is not ever a rhombus, a rhombus has acute angels and squares don't.

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3 years ago

A piece of copper wire which is 56cm long is bent to form a rectangle of area 171cm².find the length and the width of this recta

devlian [24]

Answer:

Length= 19cm

Width= 9cm

Step-by-step explanation:

let the length of the rectangle be L cm and its width be W cm.

Perimeter of rectangle= 56cm

2L +2W= 56

L +W= 56 ÷2

L +W= 28

L= 28 -W -----(1)

Area of rectangle= length ×width

LW= 171 -----(2)

Susbt. (1) into (2):

W(28 -W)= 171

28W -W²= 171 (expand)

W² -28W +171= 0 (bring everything to one side)

(W -19)(W-9)= 0 (factorise)

W-19=0 or W-9=0

W= 19 or W= 9

Subst into (1):

L=28 -19 or L= 28 -9

L=9 or L= 19

Since we usually take the longer side of the rectangle to be its length, L= 19 and hence W=9.

Therefore its length is 19cm and its width is 9cm.

3 0

3 years ago

Carissa bought a new pair of shoes that normally cost $50 for a sale price of $32.50 what was the percent of the discount

scoundrel [369]

The discount was 35%
to find that i did 32.5 / 50 and found 0.65 which means thats 32.5 is 65% of 50, but 17.5 was taken off and 17.5 is 35% of 50.

5 0

3 years ago

A standard deck of cards contains 52 cards. One card is selected from the deck.(a)Compute the probability of randomly selecting

Aneli [31]

a. There are four 5s that can be drawn, and $\binom43=4$ ways of drawing any three of them. There are $\binom{52}3=22,100$ ways of drawing any three cards from the deck. So the probability of drawing three 5s is

$\dfrac{\binom43}{\binom{52}3}=\dfrac4{22,100}=\dfrac1{5525}\approx0.00018$

In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of $\frac8{52}=\frac2{13}\approx0.15$ of getting drawn.

b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability $\frac{12}{52}=\frac3{13}\approx0.23$ of being drawn.

c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of $\frac{16}{52}=\frac4{13}\approx0.31$ .