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saul85 [17]
3 years ago
14

What type of transformation does Shape A undergo to form Shape B a

Mathematics
1 answer:
Elis [28]3 years ago
6 0

the answer is the last one: a 90° clockwise rotation
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8. In right triangle LMN shown below, altitude MK is drawn to LN from M. IF LM = 12 and LK =10, then
Elena-2011 [213]

The length of the KN is 4.4

Step-by-step explanation:

We know from Pythagoras theorem  

In a right angle ΔLMN  

Base² + perpendicular² = hypotenuse ²

From the properties of triangle we also know that altitudes are ⊥ on the sides they fall.

Hence ∠LKM = ∠NKM = 90 °

Given values-

LM=12

LK=10

Let KN be “s”

⇒LN= LK + KN

⇒LN= 10+x        eq 1

Coming to the Δ LKM

⇒LK²+MK²= LM²

⇒MK²= 12²-10²

⇒MK²= 44           eq 2

Now in Δ MKN

⇒MK²+ KN²= MN²

⇒44+s²= MN²       eq 3

In Δ LMN

⇒LM²+MN²= LN²

Using the values of MN² and LN² from the previous equations

⇒12² + 44+s²= (10+s) ²

⇒144+44+s²= 100+s²+20s

⇒188+s²= 100+s²+20s    cancelling the common term “s²”

⇒20s= 188-100

∴ s= 4.4

Hence the value of KN is 4.4  

8 0
3 years ago
Find the difference 0.2 - 0.05 =
Ugo [173]

Answer:

0.2-0.05=0.15

Step-by-step explanation:

0.2=0.20

0.20-0.05=0.15

5 0
3 years ago
Find the 90 th derivative of the function ƒ(x)=cos(x)
Inessa [10]
F(x) = cos x
f'(x) = -sin x
f''(x) = -cos x
f'''(x) = sin x
f''''(x) = cos x

90/4 = 22 Remainder 2
Therefore, 90th derivative of f(x) = cos x is -cos x.
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3 years ago
Sam drinks water at an incredible rate. She drinks 2 1/5 liters of water every 3/4 of an hour. Sam drinks water at a constant ra
lora16 [44]

Answer:

2.9 litres

or

2 14/15 litres

Step-by-step explanation:

To determine the amount of water Sam drinks in an hour, divide the total amount drunk by the number of hours

Amount drank in an hour = total litres drunk / time

2\frac{1}{5} ÷ \frac{3}{4}

\frac{11}{5} × \frac{4}{3} = \frac{44}{15} = 2\frac{14}{15} litres

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2 years ago
Which system of equations has no solutions? y - ​
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The second one on the top right
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