1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
creativ13 [48]
2 years ago
14

What dod instruction implements the dod cui program

Computers and Technology
1 answer:
Alexxandr [17]2 years ago
3 0

Answer:

oDI 5200.48 implements the DOD CUI program as required by EO 13556

Explanation:

You might be interested in
Question 7 Consider the following code:
zhannawk [14.2K]

Answer:

Melon

Explanation:

The variable "list" containts a function that returns a price that is greater than or equal to 60.0.

In the variable "fruit", the only item in the array with a price attribute set above that number is the string Melon.

3 0
1 year ago
Write a client program that writes a struct with a privateFIFO name (call it FIFO_XXXX, where XXXX is the pid that you got from
ivann1987 [24]

Answer:

client code:

#include <stdio.h>

#include <fcntl.h>

#include <sys/stat.h>

#include <sys/types.h>

#include <unistd.h>

#include <stdlib.h>

#include <string.h>

int main (void)

{

 struct values

 {

   char privateFIFO[14];

   int intbuff;

 }input;

 int fda;  // common FIFO to read to write to server

 int fdb;      // Private FIFO to read from server

 int clientID;

 int retbuff;

 char temp[14];

 clientID = getpid();

 strcpy(input.privateFIFO, "FIFO_");

 sprintf(temp, "%d", clientID);

 strcat(input.privateFIFO, temp);

 printf("\nFIFO name is %s", input.privateFIFO);

 // Open common FIFO to write to server

 if((fda=open("FIFO_to_server", O_WRONLY))<0)

    printf("cant open fifo to write");

 write(fda, &input, sizeof(input));    // write the struct to the server

 close(fda);

 // Open private FIFO to read

 if((fdb=open(input.privateFIFO, O_RDONLY))<0)

    read(fdb, &retbuff, sizeof(retbuff));

 printf("\nAll done\n");

 close(fdb);

}

server code:

#include <stdio.h>

#include <errno.h>

#include <fcntl.h>

#include <sys/stat.h>

#include <sys/types.h>

#include <unistd.h>

#include <stdlib.h>

#include <string.h>

struct values

 {

   char privateFIFO[14];

   int intbuff;

 }input;

int main (void)

{

 int fda;  //common FIFO to read from client

 int fdb;  //private FIFO to write to client

 int retbuff;

 int output;

// create the common FIFO  

 if ((mkfifo("FIFO_to_server",0666)<0 && errno != EEXIST))

       {

       perror("cant create FIFO_to_server");

       exit(-1);

}

// open the common FIFO

 if((fda=open("FIFO_to_server", O_RDONLY))<0)

    printf("cant open fifo to write");

output = read(fda, &input, sizeof(input));

// create the private FIFO

 if ((mkfifo(input.privateFIFO, 0666)<0 && errno != EEXIST))

 {

   perror("cant create privateFIFO_to_server");

   exit(-1);

 }

 printf("Private FIFO received from the client and sent back from server is: %d", output);

 //open private FIFO to write to client

if((fdb=open(input.privateFIFO, O_WRONLY))<0)

   printf("cant open fifo to read");

 write(fdb, &retbuff, sizeof(retbuff));

 close(fda);

 unlink("FIFO_to_server");

 close(fdb);

 unlink(input.privateFIFO);

}

Explanation:

3 0
3 years ago
Amy wants to make an exact replica of a specific area in an image. Which tool Amy will use?
ipn [44]

Answer:

Explanation:

.

4 0
3 years ago
Consider the two computers A and B with the clock cycle times 100 ps and 150 ps respectively for some program. The number of cyc
Kipish [7]

Answer:

Option d) B is 1.33 times faster than A

Given:

Clock time, t_{A} = 100 ps

t_{A} = 150 ps

No. of cycles per instructions,  n_{A} = 2.0

n_{B} = 1.0

Solution:

Let I be the no. of instructions for the program.

CPU clock cycle, f_{A} = 2.0 I

CPU clock cycle, f_{B} = 1.0 I

Now,

CPU time for each can be calculated as:

CPU time, T = CPU clock cycle\times clock time

T_{A} = f_{A}\times t_{A} = 2.0 I\times 100 = 200 I ps

T_{B} = f_{B}\times t_{B} = 1.0 I\times 100 = 150 I ps

Thus B is faster than A

Now,

\frac{Performance of A}{Performance of B} = \frac{T_{A}}{T_{B}}

\frac{Performance of A}{Performance of B} = \frac{200}{150}

Performance of B is 1.33 times that of A

7 0
2 years ago
Read 2 more answers
Andy wants to touch up his holiday photographs because they appear too bright and the color is washed out. Which software applic
Veronika [31]
The application andy wants to use is adobe photoshop 
5 0
3 years ago
Other questions:
  • You are attempting to update a Windows image that has been mounted under C:\mount on your local system. What command must you us
    13·1 answer
  • Which statement is true? Group of answer choices Variables cannot be assigned and declared in the same statement Variable names
    5·1 answer
  • Define a function setheight, with int parameters feetval and inchesval, that returns a struct of type heightftin. the function s
    6·1 answer
  • Web sites use _____ to track users while they are on the site.
    14·1 answer
  • This morning when Paul turned on his computer at work, it would not boot. Instead, Paul reported that he heard a loud clicking n
    15·1 answer
  • What is the component on the motherboard that confirms all devices are in working order once the computer is turned on?
    13·1 answer
  • List all the components of a computer
    14·2 answers
  • The purpose of Appetizers on the menu​
    6·2 answers
  • Consider the following code segment, which is intended to simulate a random process. The code is intended to set the value of th
    13·1 answer
  • Which online note-taking device allows students to clip a page from a website and reuse it later?
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!