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2 years ago

Help me ? 10 450 15 675 20 900

Mathematics

1 answer:

Shtirlitz [24]2 years ago

4 0

Answer:

Y=45x

Step-by-step explanation:

Y = f(x)

If you plot a chart, you can find that relation is just a linear relation. So y = mx + c

By putting any one case into the equation, you can find c = 0 and m = 45

Retest the equation for other cases to ensure u are correct

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HELP PLEASE I NEED TO CHECK OFF THE TWO FUNCTIONS USED TO CREATE THE GRAPH BELOW

Lelu [443]

Linear and trigonometric

6 0

3 years ago

Help Me With This Please

Cerrena [4.2K]

8. complementary angles = 90°
3x+3+10x-4 = 90
13x-1 = 90
13x = 91
so x = 91/13= 7
then K = 3(7)+3 = 24°
so L = 10(7)-4 = 70-4 = 66°

9. P is three less than twice of Q
so P = 2Q-3
supplementary angles = 180°

P+Q = 180
(2Q-3)+Q = 180
3Q-3 = 180
3Q = 183
so Q = 183/3 = 61°
then P= 2(61)-3 = 122-3 = 119°

10. B is two more than three times of C so B= 3C+2
complementary angles = 90°

B+C= 90
(3C+2)+C=90
4C+2=90
4C= 88
so C= 22°
then B = 3(22)+2= 66+2 = 68°

8 0

4 years ago

A cylinder has a base diameter of 8 inches and a height of 7 inches. What is its volume in cubic inches, to the nearest tenths p

DaniilM [7]

Answer:

351.9 cubic in

Step-by-step explanation:

The volume of a cylinder is hr²π.

r is half the diameter, so 8/2 is 4.

Plug in your h and r and get:

7 * 4² * π

7 * 16 * π

112π

Multiply the π and you'll get about 351.9 cubic in

7 0

3 years ago

- Бу - 10x = 45 -Зу + 10x = -5 x= y=

katovenus [111]

Answer:

X= -11/6. Y=-40/9

Step-by-step explanation:

3 0

3 years ago

Cable Strength: A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the ca

KatRina [158]

Answer:

95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

Step-by-step explanation:

We are given that the engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb.

Since, in the question it is not specified that how much confidence interval has be constructed; so we assume to be constructing of 95% confidence interval.

Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean breaking weight = 768.2 lb

s = sample standard deviation = 15.1 lb

n = sample of cables = 45

$\mu$ = population mean breaking strength

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.02 < $t_4_4$ < 2.02) = 0.95 {As the critical value of t at 44 degree

of freedom are -2.02 & 2.02 with P = 2.5%}

P(-2.02 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.02) = 0.95

P( $-2.02 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $768.2-2.02 \times {\frac{15.1}{\sqrt{45} } }$ , $768.2+2.02 \times {\frac{15.1}{\sqrt{45} } }$ ]

= [763.65 lb , 772.75 lb]

Therefore, 95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

3 0

4 years ago