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tatyana61 [14]
3 years ago
14

Can anyone explain how to do this? I looked at the book and now I'm even more confused. 50 points

Mathematics
1 answer:
katrin [286]3 years ago
8 0

The piecewise function is basically the result of two different functions combined together. If x is 0 or larger, then h(x) = x+4. Otherwise, if x < 0, then h(x) = -x-4

No matter what number you pick for x, the h(x) function will be used in some way. So the domain is the set of all real numbers. To write this in interval notation, we write (-\infty, \infty) which means we start off at negative infinity and go to positive infinity. This is basically saying "the entire real number line". Since we can't actually reach either infinity, we always use parenthesis with them. <u>Never</u> use square brackets with either infinity

From the graph (see attached image below), we see that (0,-4) is the lowest point. This means y = -4 is the smallest y output possible, though we can't actually reach it because of the open circle at (0,-4). We can get any other larger y value. So the range is therefore: (-4, \infty) meaning we start at -4 and head off to positive infinity. The curve parenthesis next to -4 the reader "exclude -4 as part of the range". There is an open hole or gap here. Another way to state the range is to write y > -4

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Answer this pls..................​
Sindrei [870]

Answer:

so we know:

total of 20 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry has a total of 14 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14

8 students are in physics

1 2 3 4 5 6 7 8

3 are in all of them

1 2 3

1) underline the main 3

total of 20 students

<u>1 2 3 </u>4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry has a total of 14 students

<u>1 2 3</u> 4 5 6 7 8 9 10 11 12 13 14

8 students are in physics

<u>1 2 3 </u>4 5 6 7 8

2) lets bold the physics students, if you are in physics you have to do chem so that means 8 of the chem students also take physics.

total

<u>1 2 3 </u>4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry

<u>1 2 3</u> 4 5 6 7 8 9 10 11 12 13 14

physics

<u>1 2 3 </u>4 5 6 7 8

3) now we bring biology into the "equation"

off the bat we know 3 are definitely in Biology.

so if 4 study ONLY biology we can cross them off our list see the {}

total

<u>1 2 3 </u>4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

<u>1 2 3</u> 4 5 6 7 8 {9 10 11 12} 13 14

physics

<u>1 2 3 </u>4 5 6 7 8

biology

<u>1 2 3 </u>

<u />

4) so we have a total of 20 students, 3 in all of the classes <u>(underlined)</u>, 8 in physics (bolded). If there 14 in chemistry, 4 take ONLY chemistry {}, 8 take chemistry as well (bolded), that leaves two students, so they must belong in biology. lets<em> italicise</em> them.

total

<em><u>1 2 3 </u></em>4 5 6 7 8 {9 10 11 12} <em>13 14</em> 15 16 17 18 19 20

chemistry

<em><u>1 2 3</u></em><em> </em>4 5 6 7 8 {9 10 11 12} <em>13 14</em>

physics

<em><u>1 2 3</u></em><u> </u>4 5 6 7 8

biology

<em><u>1 2 3 </u></em><em> 13 14</em>

<u />

5) out of our total of 20 students we know 14 of the students classes, so the remaining six must be in biology.

<u>1 2 3 </u>4 5 6 7 8 {9 10 11 12} <em>13 14</em> 15 <em>16 17 18 19 20</em>

chemistry

<u>1 2 3</u> 4 5 6 7 8 {9 10 11 12} <em>13 14</em>

physics

<u>1 2 3 </u>4 5 6 7 8

biology

<u>1 2 3 </u><em>13 14</em> 15 <em>16 17 18 19 20</em>

6) so that was our "diagram" so now lets count how many are in chemistry and biology but NOT physics.

<u>1 2 3 </u>4 5 6 7 8 {9 10 11 12} <em>13 14</em> 15 <em>16 17 18 19 20</em>

chemistry

<u>-1 2 3</u> 4 5 6 7 8- {9 10 11 12} <em>13 14</em>

physics

<u>-1 2 3 </u>4 5 6 7 8-

biology

<u>-1 2 3 -</u><em>13 14</em> 15 <em>16 17 18 19 20</em>

there are 14 students in chemistry and 11 in biology, 5 of them are in both classes so 14-5= 9 and 11-5= 6 9+6=16. BUT 8 of those sixteen are also in -physics- so we arent counting them, we put those students in dashes. so lets count the students out of the dashes. so<em> twelve</em> of them are in chemistry and biology but not physics.

7) so how many are in just biology but not the other classes? lets look at the graph.

<u>1 2 3 </u>4 5 6 7 8 {9 10 11 12} <em>13 14</em> 15 <em>16 17 18 19 20</em>

chemistry

<u>1 2 3</u> 4 5 6 7 8 {9 10 11 12} <em>13 14</em>

physics

<u>1 2 3 </u>4 5 6 7 8

biology

<u>1 2 3 </u><em>13 14</em> 15 <em>16 17 18 19 20</em>

in the class of biology students 1 2 3 13 and 14 take other classes that leaves students 15 16 17 18 19 and 20. so 6 students take ONLY biology.

sorry its long but i hope this helps!

3 0
3 years ago
A garden is a rectangle 100 feet long and 50 feet wide. The portion of the garden devoted to herbs is 10 feet by 10 feet. The re
lys-0071 [83]
4,900 sq feet are given for growing vegetables
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3 years ago
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-5/4c - 1/4 = -3/4 + 5/8c  Please Help
Svetradugi [14.3K]
The answer is -8/15 because you need to cancel out the variables first
3 0
2 years ago
Read 2 more answers
Or lingneeds 2 yards of fabric for a raft project .she has 3 feet already. how many inches of fabric that she need still need?
otez555 [7]
2 yards = 72 inches
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7 0
3 years ago
The safe load, L, of a wooden beam supported at both ends varies jointly as the width, w, and the square of the depth, d, and in
MakcuM [25]

Answer:

joint variation means L (safe load) is directly proportional to both w and d2

inverse proportionality means L = k/l

So the equation is:

L = k(wd2/l)

You are given:

w = 6 in

d = 5 in

l = 12 ft

L = 7666 lbs

7666 = k(6*52/12)

Solve for the constant, k.

7666 = k (6*25/12)

7666 = k (150/12)

7666 = k (12.5)

613.28 lbs/(ft.in3) = k

Use this k-value to solve for L in the last part of the question.

What safe load, L would a beam 3 in. wide, 7 in. deep and 15 ft long of the same material support? (Round off your answer to the nearest pound.)

w = 3 in

d =7 in

l = 15 ft

k = 613.28 lbs/(ft.in3)

Final Safe load = 6010.144 lbs *** Edited for clarity and to fix a multiplication erro

5 0
1 year ago
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