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Yuri [45]
2 years ago
13

Which rectangles have the same areas but greater perimeters than the one shown below? Choose all that apply.

Mathematics
1 answer:
Firlakuza [10]2 years ago
5 0

The  rectangles have the same areas but greater perimeters are 12 ft by 3 ft, 9 ft by 4 ft and 18 ft by 2 ft.

<h3>What is area?</h3>

Area is the amount of space occupied by a two dimensional shape or object.

A rectangle is shown with a length and height of 6 ft. Hence:

Area = (6 * 6) = 36 ft²

Perimeter = 2(6 + 6) = 24 ft

For 12 ft by 3 ft:

Area = (12 * 3) = 36 ft²

Perimeter = 2(12 + 3) = 30 ft

For 9 ft by 4 ft:

Area = (9 * 4) = 36 ft²

Perimeter = 2(9 + 4) = 26 ft

For 8 ft by 3 ft:

Area = (8 * 3) = 24 ft²

Perimeter = 2(8 + 3) = 24 ft

For 7 ft by 4 ft:

Area = (7 * 4) = 28 ft²

Perimeter = 2(7 + 4) = 26 ft

For 18 ft by 2 ft:

Area = (18 * 2) = 36 ft²

Perimeter = 2(18 + 2) = 40 ft

The  rectangles have the same areas but greater perimeters are 12 ft by 3 ft, 9 ft by 4 ft and 18 ft by 2 ft.

Find out more on area at: brainly.com/question/25292087

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3 On a coordinate grid, the location of a lighthouse is at L, and the location of a buoy is at B. At noon, a ship is at the midp
Zarrin [17]

Answer:

(\frac{1}{2}, 2)

Step-by-step explanation:

Using the midpoint formula, M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}), we can find the coordinates that represents the position of the ship at noon.

Let L(-4, 7) = (x_1, y_1) (given on the coordinate plane)

B(5, -3) = (x_2, y_2) (given also)

Plug in the values into the formula and solve as follows:

M(\frac{-4 + 5}{2}, \frac{7 +(-3)}{2})

M(\frac{1}{2}, \frac{7 - 3}{2})

M(\frac{1}{2}, \frac{4}{2})

M(\frac{1}{2}, 2)

Position of the ship at noon is best represented at (\frac{1}{2}, 2)

5 0
4 years ago
Not a question, but a suggestion.
USPshnik [31]

Answer:

thank you! you too

6 0
3 years ago
Read 2 more answers
Triangle a' B' c' is dilation of triangle abc about point p. Is this a reduction or enlargement<br>​
Yuliya22 [10]

Enlargement

Hope this helps :)

8 0
3 years ago
For which of the following equations are x = 5 and x = –5 both solutions?
Minchanka [31]
Short Answer B
Argument
A
A will give you x = +/- 5i 
x^2 + 25 = 0
x^2 = - 25       Take the square root.
sqrt(x^2) = +/- sqrt(-25)
x = +/- (5)i which is a complex number.


B
Is the answer
x^2 = 25
sqrt(x)^2 = sqrt(25)
x = +/- 5

C
Can't be factored just by looking at it. You can show that C is not true just by putting 5 into the equation
f(x) = x^2 + 10x - 25
f(5) = 25 + 10*5 - 25
f(5) = 50
C is not true.

D
D can be eliminated as C was
f(x) = x^2 - 5x - 25
f(5) = -25 ( l'll let you show this is not true). 5 is not a solution because it does not make f(x) = 0
6 0
3 years ago
Read 2 more answers
Pleaseeee helpppp !!!!!!! Will mark Brianliest !!!!!!!!!!!!
Ksivusya [100]
The answer is this




FG=69

5 0
3 years ago
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