If scores on an exam follow an approximately normal distribution with a mean of 76.4 and a standard deviation of 6.1 points, then the minimum score you would need to be in the top 2% is equal to 88.929.
A problem of this type in mathematics can be characterized as a normal distribution problem. We can use the z-score to solve it by using the formula;
Z = x - μ / σ
In this formula the standard score is represented by Z, the observed value is represented by x, the mean is represented by μ, and the standard deviation is represented by σ.
The p-value can be used to determine the z-score with the help of a standard table.
As we have to find the minimum score to be in the top 2%, p-value = 0.02
The z-score that is found to correspond with this p-value of 0.02 in the standard table is 2.054
Therefore,
2.054 = x - 76.4 ÷ 6.1
2.054 × 6.1 = x - 76.4
12.529 = x - 76.4
12.529 + 76.4 = x
x = 88.929
Hence 88.929 is calculated to be the lowest score required to be in the top 2%.
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A cube has 6 faces. The surface area of a cube is 6 times the area of one face.
SA = 6s^2
SA = 6 * 6cm^2
SA = 6 * 36cm^2
SA = 216cm^2
Answer: 0.02 per year
Step-by-step explanation:
When given the per capita birth rate and the per capita death rate, the per capita growth rate can be calculated as:
= per capita birth rate - per capita death rate
= 0.11 - 0.09
= 0.02/year
= 2% per year
Answer:umm I think to do that you need to สะเดมแคพสพว เุ่ะมำงกรด พรพเ่พยวพ
Step-by-step explanation:ระะทืะยะะืะนะทะ ถระทพนดทเรทเสเยเสเรเาดยเสะมะนเสเร้าเสพ
35 has 4 divisors, hence two factor pairs: 1*35 and 5*7. Each corresponds to a set of perfect squares that differ by 35
One pair is ((35±1)/2)^2 = {17^2, 18^2} = {289, 324}
The other is ((7±5)/2)^2 = {1^2, 6^2} = {1, 36}
