Question

For all values of x, x² + 6x - 2 = (x+p)² + q Find the value of p and the value of q.

Answer 1

Step-by-step explanation:

${x}^{2} + 6x - 2 = {x}^{2} + 2px + {p}^{2} + q$

$2p = 6$

${p}^{2} + q = - 2$

$p = 3$

${3}^{2} + q = - 2$

$q = - 11$

p=3, q=-11