Answer:
3x²
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Terms/Coefficients
- Functions
- Function Notation
Step-by-step explanation:
<u>Step 1: Define</u>
[Given] f(x) = x²
[Solve] f(x) + f(x) + f(x)
<u>Step 2: Find</u>
- Combine like terms: 3f(x)
- Substitute in function: 3(x²)
- Multiply: 3x²
Answer:
1. $20280
2. 117 h
Step-by-step explanation:
1.
to know the value of the car we have to add all the monthly payments with the $ 3000 that she paid at the beginning
x = car value
x = $3000 + 48 * $360
x = $3000 + $17280
x = $20280
The total cost of the car is $20280
2.
To know how many hours I work in total we have to add the hours I work in each day 5 times with the 57 hours I work the following week
x = hours that work in all
x = 5 * 12 + 57
x = 60 + 57
x = 117
work for 117 hours in all
34 “pupils” like both apples and oranges
Answer:
The solutions are a₁ = -4/19 i, a₂ = 4/19 i and a₃ = -1/4
Step-by-step explanation:
Given the equation 76a³+19a²+16a=-4, for us to solve the equation, we need to find all the factors of the polynomial function. Since the highest degree of the polynomial is 3, the polynomial will have 3 roots.
The equation can also be written as (76a³+19a²)+(16a+4) = 0
On factorizing out the common terms from each parenthesis, we will have;
19a²(4a+1)+4(4a+1) = 0
(19a²+4)(4a+1) = 0
19a²+4 = 0 and 4a+1 = 0
From the first equation;
19a²+4 = 0
19a² = -4
a² = -4/19
a = ±√-4/19
a₁ = -4/19 i, a₂ = 4/19 i (√-1 = i)
From the second equation 4a+1 = 0
4a = -1
a₃ = -1/4
<h3>
Answer: Choice A</h3>
is not the same as 
The base of the log is p, while the base of the exponential is b. The two don't match. If it said 
then it would be a valid statement since the bases are both p.
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Extra info:
Choice B is a valid statement because Ln is a natural log with base 'e'
Choice C is valid as any square root is really something to the 1/2 power
Choice D is valid for similar reasons mentioned earlier
