25. Find the number whose square is 3 less than 4
times the number.
2 answers:
Answer:

Step-by-step explanation:
Let the number be x
<u>Given condition:</u>
x² = 4x - 3
Subtract 4x to both sides and add 3 to both sides
x² - 4x + 3 = 0
Using mid-term break
x² - 3x - x + 3 = 0
Take common
x(x-3) - 1(x-3) = 0
Take (x-3) common
(x - 3)(x - 1) = 0
<u>Using zero's method</u>
Either,
x - 3 = 0 OR x - 1 = 0
x = 3 OR x = 1
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Answer:
1 or 3
Step-by-step explanation:
hope this helps:)
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