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kumpel [21]
2 years ago
14

25. Find the number whose square is 3 less than 4 times the number.

Mathematics
2 answers:
SOVA2 [1]2 years ago
8 0

Answer:

\huge\boxed{\sf x =\{3,1\}}

Step-by-step explanation:

Let the number be x

<u>Given condition:</u>

x² = 4x - 3

Subtract 4x to both sides and add 3 to both sides

x² - 4x + 3 = 0

Using mid-term break

x² - 3x - x + 3 = 0

Take common

x(x-3) - 1(x-3) = 0

Take (x-3) common

(x - 3)(x - 1) = 0

<u>Using zero's method</u>

Either,

x - 3 = 0     OR     x - 1 = 0

x = 3          OR      x = 1

\rule[225]{225}{2}

KonstantinChe [14]2 years ago
4 0

Answer:

1 or 3

Step-by-step explanation:

hope this helps:)

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Let U={1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, A={1, 2, 3, 4, 5}, B={1, 3, 5, 7} Find A' ∩ B
sineoko [7]

Here given that:

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Here let's first find the set A' , by using formula:

→ A' = U - A

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