Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative

2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function

3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
Answer:
6541.7 mm³ (nearest tenth)
Step-by-step explanation:

Given that the height is 40mm, h= 40mm.
Diameter= 2(radius)
Radius of cone
= 25 ÷2
= 12.5mm
Volume of cone

= 6541.7 mm³ (nearest tenth)
Answer:
y=6/5
Step-by-step explanation:
Hope this helps! Sorry if its wrong