What is the slope of the line passing through (9,-6) and (5, 10)?
2 answers:
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Answer:
Step-by-step explanation
We have given that equation of line a+4b=0
⇒4b= -a
⇒
slope of line =
⇒ is negative therefore it lies into 4th quadrant
By, Pythagoras theorem
by putting value of P= -1 & B=4
the value of
with the given condition
i.e. ∈ (3π/2, 2π)
now,
All the points that are 6 units from (-1, 1) are those on the circle
(x+1)^2 +(y-1)^2 = 36
For y=0, the two points of interest satisfy
(x+1)^2 +1 = 36
(x+1)^2 = 35 . . . . . . subtract 1
x+1 = ±√35
x = -1±√35
The points you seek are (-1-√35, 0) and (-1+√35, 0), about (-6.916, 0) and (4.916, 0).
(x+1)^2 +(y-1)^2 = 36
For y=0, the two points of interest satisfy
(x+1)^2 +1 = 36
(x+1)^2 = 35 . . . . . . subtract 1
x+1 = ±√35
x = -1±√35
The points you seek are (-1-√35, 0) and (-1+√35, 0), about (-6.916, 0) and (4.916, 0).