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3 years ago

Round this number to two significant figures. 8,468

Mathematics

2 answers:

Jlenok [28]3 years ago

8 0

8500

10^3 x 8.5 = 8500

tigry1 [53]3 years ago

7 0

Answer:

Rounding to two significant figures the number became

$8468=8\bar{5}00$

Step-by-step explanation:

Given : Number 8,468

To find : Round this number to two significant figure ?

Solution :

Rounding to two significant figure we have to estimate or round the values in terms of zeros.

Rounding the number to hundreds value,

As 6 is greater than 5 so 4 rounds to 5 and rest became zero.

i.e. $8468=8\bar{5}00$

bar means the estimated value.

Therefore, Rounding to two significant figures the number became

$8468=8\bar{5}00$

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2) Given: lines a and b are parallel Prove: m<1 = m<8

monitta

Explanation:

* Demonstrate that the related angles are the same.

* Demonstrate that different interior angles are equivalent.

* Demonstrate the adjacent interior angles are supplementary.

* Demonstrate the adjacent external angles are not mutually exclusive.

* Show that the lines in a plane are perpendicular to the same axis.

<1 and <8 are the same because they are alternate exterior angles that means that they are

Opposite sides of the transversal.

And that they are on the exterior side of the parallel lines.

Now because of that they have the same measures no matter what so would

<2 and <7

<3 and <6

<4 and <5

6 0

3 years ago

GE bisects DGF , m_ CGD= 2x - 2, m2 EGF= 37, m CGF = 7x + 2 mZCGD = mZCGF =

stira [4]

Answer:

m<CGD = 26°

m<CGF = 100°

Step-by-step explanation:

m<CGD = 2x - 2

m<EGF = 37

m<CGF = 7x + 2

Since GE bisects <DGF, m<DGF = 2*m<EGF.

m<DGF = 2*37 = 74°

m<CGD + m<DGF = m<CGF (angle addition postulate)

(2x - 2) + (74) = (7x + 2)

Find the value of x using the equation above.

2x - 2 + 74 = 7x + 2

Collect like terms

2x + 72 = 7x + 2

-2 + 72 = 7x - 2x

70 = 5x

70/5 = 5x/5

14 = x

x = 14

m<CGD = 2x - 2

Plug in the value of x

m<CGD = 2(14) - 2 = 28 - 2

m<CGD = 26°

m<CGF = 7x + 2

m<CGF = 7(14) + 2 = 98 + 2

m<CGF = 100°

4 0

3 years ago

In a T-test, if your n=459, your DF is: A. 459 B. 460 C. 458 D. A&C

Stels [109]

Answer:

DF = 458

Step-by-step explanation:

In statistics, T-test have an extensive application. T-tests are used in hypothesis testing or inference about the population mean when the population standard deviation is not known. Nevertheless, they are used in making inference in paired samples or dependent samples t-test as well as independent samples.

The degrees of freedom, DF, is a characteristic of the student's t distribution which is used in T-tests. In a simple T-test;

DF = n - 1

where n is the sample size

Given n is 459, DF = 459 - 1 = 458

Therefore, DF = 458

6 0

3 years ago

What is the inverse of the function f(x) =2x-10

GalinKa [24]

$f(x) =2x-10 \\ y=2x-10 \\ \\ x = 2y-10 \\ 2y = x+10 \\ y= \frac{1}{2} x+5 \\ \\ \\ \boxed {f^{-1}(x)= \frac{1}{2} x+5}$

6 0

3 years ago

Read 2 more answers

The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches. Men the same

masha68 [24]

Answer: The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.

Step-by-step explanation:

Let x and y area the random variable that represents the heights of women and men.

Given : The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches.

i.e. $\mu_1 = 64$ $\sigma_1=2.7$

Since , $z=\dfrac{x-\mu}{\sigma}$

Then, z-score corresponds to a woman 6 feet tall (i.e. x=72 inches).

[∵ 1 foot = 12 inches , 6 feet = 6(12)=72 inches]

$z=\dfrac{72-64}{2.7}=2.96296296\approx2.96$

Men the same age have mean height 69.3 inches with standard deviation 2.8 inches.

i.e. $\mu_2 = 69.3$ $\sigma_2=2.8$

Then, z-score corresponds to a man 5'10" tall (i.e. y =70 inches).

[∵ 1 foot = 12 inches , 5 feet 10 inches= 5(12)+10=70 inches]

$z=\dfrac{70-69.3}{2.8}=0.25$

∴ The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.

6 0

3 years ago