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lys-0071 [83]
2 years ago
9

Find tan please.make sure to simplify if needed

Mathematics
1 answer:
Alina [70]2 years ago
7 0
What do u want me to solve there is no photo
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melamori03 [73]

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A. (2,2), (3,2), (3,3), (3,4), (4,6), (5,4), (5,7), (6,4), (6,6), (7,7)

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Find the area of the parallelogram below.
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The area is 40 because you do 12 times two then eight times two then add the awnsers

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Sauron [17]

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Step-by-step explanation:

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12 prob

Step-by-step explanation:

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Two vertical poles of length 10 and 12 ​feet, respectively, stand 17 feet apart. A cable reaches from the top of one pole to the
Marat540 [252]

Answer:

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433} ft

Step-by-step explanation:

let length of calble = L

distance from 10-foot pole = x ft

Moving from the top of the 10-foot pole to point x, we have

From the diagram that

x^{2} +10^{2}=L_{1} ^{2}  \\x^{2} + 100 = L_{1} ^{2}

Take the square root of both sides

\sqrt{x^{2}+100}=\sqrt{L_{1} ^{2}}\\  \sqrt{x^{2}+100}= L_{1}

Moving from point x to the top of the 12-foot pole, we have

From the diagram that

(17-x)^{2}+12^{2}=L_{2} ^{2}   \\289-34x+x^{2} +144=L_{2} ^{2}\\x^{2} -34x+433=L_{2} ^{2}

Take the square root of both sides

\sqrt{x^{2}-34x+433}=\sqrt{L_{2} ^{2}}  \\\sqrt{x^{2}-34x+433}=L_{2}

Amount of cable used, L = L1 + L2

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433}

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3 years ago
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