Answer:
x^0 y^-3 / x^2 y^-1
= 1 / x^2 y^-1 (y^3) ...because x^0 = 1 and [(y^-1) (y^3)] = y^2
= 1/(x^2 y^2)
-6m+19
1/2(-12m+38)
All we have to do is simply distribute the 1/2.
1/2(-12m) + 1/2(38)
(-6m) + 19
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![\sf{14(\sqrt[3]{x}) }](https://tex.z-dn.net/?f=%5Csf%7B14%28%5Csqrt%5B3%5D%7Bx%7D%29%20%7D)
Step-by-step explanation:
![5(\sqrt[3]{x})+9(\sqrt[3]{x})\\\\(5+9)(\sqrt[3]{x})\\\\14(\sqrt[3]{x})](https://tex.z-dn.net/?f=5%28%5Csqrt%5B3%5D%7Bx%7D%29%2B9%28%5Csqrt%5B3%5D%7Bx%7D%29%5C%5C%5C%5C%285%2B9%29%28%5Csqrt%5B3%5D%7Bx%7D%29%5C%5C%5C%5C14%28%5Csqrt%5B3%5D%7Bx%7D%29)
Add 11 to both sides:
-4=-2t
divide 2 by both sides
2=t
Hope it helps! Comment if you have any questions!
Answer:
B. -4x+5y=40
Step-by-step explanation:
y * 5= (4/5 x + 8) * 5
5y = 4x + 40
-4x + 5y =40
