18 kg of 15% copper and 72 kg of 60% copper should be combined by the metalworker to create 90 kg of 51% copper alloy.
<u>Step-by-step explanation:</u>
Let x = kg of 15% copper alloy
Let y = kg of 60% copper alloy
Since we need to create 90 kg of alloy we know:
x + y = 90
51% of 90 kg = 45.9 kg of copper
So we're interested in creating 45.9 kg of copper
We need some amount of 15% copper and some amount of 60% copper to create 45.9 kg of copper:
0.15x + 0.60y = 45.9
but
x + y = 90
x= 90 - y
substituting that value in for x
0.15(90 - y) + 0.60y = 45.9
13.5 - 0.15y + 0.60y = 45.9
0.45y = 32.4
y = 72
Substituting this y value to solve for x gives:
x + y = 90
x= 90-72
x=18
Therefore, in order to create 90kg of 51% alloy, we'd need 18 kg of 15% copper and 72 kg of 60% copper.
Answer:
21.8
Step-by-step explanation:
1.9 + 9 = 10.9
10.9 x 2 = 21.8
https://socratic.org/questions/how-do-you-find-the-area-of-the-region-bounded-by-the-polar-curves-r-3-2cos-thet#112305
go to link for the answer
Are you asking what 6 times 4 is?
Answer:
24
Answer:
y=4/3x-6
Step-by-step explanation:
y=mx+b
m= 4/3
b= -6
