Answer: Choice B) ![\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D)
Work Shown:
![\sec^2(\theta) = \tan^2(\theta) + 1\\\\\sec^2(\theta) = (\tan(\theta))^2 + 1\\\\\sec^2(\theta) = (-1)^2 + 1\\\\\sec^2(\theta) = 2\\\\\sec(\theta) = \sqrt{2}\\\\](https://tex.z-dn.net/?f=%5Csec%5E2%28%5Ctheta%29%20%3D%20%5Ctan%5E2%28%5Ctheta%29%20%2B%201%5C%5C%5C%5C%5Csec%5E2%28%5Ctheta%29%20%3D%20%28%5Ctan%28%5Ctheta%29%29%5E2%20%2B%201%5C%5C%5C%5C%5Csec%5E2%28%5Ctheta%29%20%3D%20%28-1%29%5E2%20%2B%201%5C%5C%5C%5C%5Csec%5E2%28%5Ctheta%29%20%3D%202%5C%5C%5C%5C%5Csec%28%5Ctheta%29%20%3D%20%5Csqrt%7B2%7D%5C%5C%5C%5C)
Note: secant is positive in quadrant Q4, when theta is between 3pi/2 radians and 2pi radians (270 degrees and 360 degrees). So that's why we don't consider the minus form of the plus minus.
Answer:
√8
Step-by-step explanation:
√2x√2x√2 is 2x2x2 which is 8 then the square root √8.
<h3>
Answer: 4900 mph</h3>
Work Shown:
30 min = 30/60 = 0.5 hours
distance = rate*time
rate = distance/time
rate = (2450 miles)/(0.5 hours)
rate = (2450/0.5) mph
rate = 4900 mph
For the sake of comparison, a typical commercial passenger jet can reach max speeds of about 600 mph.
780, or C, is correct. Since 9.75 is 1/80th of the actual measurement, we can set up an equation like this:
9.75 = 1/80x
Then multiply each side by 80:
780 = x
The actual building's height is 780 ft.
We can check this answer by plugging in 780 for x in the original equation:
9.75 = 1/80(780)
9.75 = 9.75
Check! <span>✓</span>
I can't read the first one and I also don't know