Answer:
16. -7x-14
17. -20+5y
18. -8b+8
19. -16c-12
20. 5w+40
21. -12x+6
22. 2z-4
23. -28p-28
24. -9t+54
25. Can't tell what this problem is. The picture cuts out.
26. -27+21p
27. 9k-27
28. -7b+9
29. 30t+12
30. 7v-28
Step-by-step explanation:
Answer:
The least value of (r+s) is (12+14)=26
Step-by-step explanation:
Well, first let us solve equation of 11(s-1)=13(r-1), which results in 11s-11=13r-13. Hence, 11s+2=13r. It is stated that r and s both are integers and greater than 1.
To make sure that r and s are integers, the least value of s must be equal to 14 (s=14) then the least value of r becomes 12 (r=12).
Finally, the least value of (r+s) is (12+14)=26.
In this problem you will need to use the Pythagorean theorem (c^2=a^2+b^2).
The a and b represents the two edges, while c is the diagonal side and it is called the hypotenuse. Since you already know what the hypotenuse is and what one of the sides already are you just have to use the problem: c^2-a^2=b^2. Then if you plug the data you already have into the problem you will get 10^2-6^2=b^2. That then equals 100-36=b^2. Then you subtract and get b^2=64. Then you square root both sides and you get the answer b=8.
I think the answer is 42.
Answer:
It’s 4
Step-by-step explanation:
2+2=4
can you mark me brainliest
