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kap26 [50]
2 years ago
5

The zigzag crystal vase has height 20 centimeters. The cross sections parallel to the base are always rectangles that are 12 cen

timeters wide by 6 centimeters long.
Mathematics
1 answer:
Vinil7 [7]2 years ago
6 0

Answer:

14440cm3

Step-by-step explanation:

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Um avião levanta voo na cidade de Vitória - ES com destino a São Paulo - SP. Durante os dez primeiros minutos de voo, sua veloci
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Responda:

GRÁFICO DE TEMPO DE VELOCIDADE

Explicação passo a passo:

Para a pergunta, encontre o gráfico de velocidade-tempo no anexo.

O gráfico que melhor representa a velocidade desse avião em função do tempo é o gráfico velocidade-tempo. O gráfico de velocidade e tempo é um gráfico que representa o movimento de um objeto esquematicamente usando linhas. Ele é plotado em um plano de coordenadas com o eixo xe o eixo y.

A função de velocidade é posicionada no eixo y, enquanto o tempo gasto ao longo da viagem está no eixo x.

Pelo anexo, pode-se ver que o avião acelera em OA, possui velocidade constante em AB e CD e tem aceleração (desaceleração) negativa em BC e DE.

4 0
4 years ago
Daniela and Jack are hiking a steady incline. They use their GPS device to determine their elevation every 15 minutes. At 15 min
kow [346]

Answer:

h=40t+9700

where the elevation, h, is in feet and time, t, is in minutes.

Step-by-step explanation:

At the time, t_1=15 min, the elevation, h_1= 10,300 feet and

at the time t_2= 30 min, the elevation, h_2=10,900 feet.

As they are hiking a steady incline, so the change in the elevation with respect to time will be constant.

So, there will be a linear relationship between the elevation and the time.

Let h be the elevation at any time instant t, so the linear relation among these quantities is

h=mt+C_0\;\cdots(i)

where m is the rate of change of elevation with respect to time and C_0 is constant.

The change in the elevation, \Delta h=h_2-h_1= 10,900-10,300=600 feet.

and the change in time, \Delta t=t_2-1_1=30-15=15 min.

So, change in the elevation in unit time,

m=\frac{\Delat h}{\Delta t}=\frac{600}{15}=40 feet/min.

Now, from equation (i)

h=40t+C_0

As the elevation, h=h_1 at time t=t_1, so

10,300=40\times15+C_0

\Rightarrow C_0=9700

Hence, the required equation is

h=40t+9700

where the elevation, h, is in feet and time, t, is in minutes.

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