Answer:
A = 1,144 ft²
Step-by-step explanation:
The base of the quadrilateral is also x. We know this since there are 2 90° angles, there fore the other 2 angles are also 90°, making the top and bottom sides of the quadrilateral parallel to each other, and equal in measure.
Since the entire base of the yard is 2x, the base of the triangle is x.
The area of the triangle is
A = (1/2)bh where b is the base, and h is the height
For this example...
A = (1/2)x(44) (x is the base, and 44 is the height)
So
A = (1/2)(44)x
A = 22x
The area of the quadrilateral is
A = LW
A = 44x
The total area of the yard is
A = 22x + 44x
A = 66x
We are told that the entire area is 3,462. so
3,462 = 66x now solve for 'x'
3,462/66 = x (divide both sides by 66)
52 = x
So the area of the picnic tables is the area of the triangle, which is
A = 22(52) = 1,144 ft²
Answer:
8
Step-by-step explanation:
3x +2x - 5 = 35 to rearrange makes it easier
then, add 3x and 2x which gives you 5x - 5 = 35
then using addition property of equality (APOE) add 5 to both sides which then cancels out the 5 on the left side of the equation and then add 5 to the right side which makes it 40. Then your equation looks like 5x = 40. then using division property of equality, divide by 5 on both sides and 40/5= 8!
Answer:
The height of the lighthouse is approximately 166.6 feet.
Step-by-step explanation:
Let the height of the lighthouse be represented by s, then;
Tan 48° = (opposite) ÷ (adjacent)
Tan 48° = s ÷ 150
⇒ s = 150 × Tan 48°
= 150 × 1.1106
= 166.59
s ≅ 166.6 feet
Therefore, the height of the lighthouse is approximately 166.6 feet.
Answer:
5 hours
Step-by-step explanation:
Let s and w represent hours spent traveling south and west, respectively. The problem statement tells us ...
s + w = 8 . . . . . . total trip time
344s + 351w = 2773 . . . . total mileage (using d = s·t)
By Cramer's rule, we can find the value of s as ...
s = (1(2773) -351(8))/(1(344) -351(1)) = -35/-7 = 5
The plane was heading south for 5 hours.
_____
<em>Comment on Cramer's rule</em>
For the equations ...
ax +by = c
dx +ey = f
The solution for x can be found to be ...
x = (bf-ec)/(bd-ea)
Similarly, the solution for y is ...
y = (cd-fa)/(bd-ea)
parallel lines is the answer