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Elanso [62]
3 years ago
6

La somme de l age de Anaise de sa mère et de sa grand mère est égale a 130 anaise a le tière de l age de sa mere s mere a le dou

ble de se lui d esa grand mere
Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
7 0

Answer:

For people who want to answer this(not me) here is a translation:

La somme de l age de Anaise de sa mère et de sa grand mère est égale a 130 anaise a le tière de l age de sa mere s mere a le double de se lui d esa grand mere

is =

The sum of the age of Anaise of his mother and of his grandmother is equal to 130 anaise of the age of his mother s mother to double his of his grandmother

hope this helps!

stealth61 [152]3 years ago
3 0
Headshot snipe (use english)
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A 17-inch candle is lit and burns at a constant rate of 1.3 inches per hour. Let t represent the number of hours since the candl
pshichka [43]

Answer

Since the lyla deleted it actually for a good reason let me explain. But you dont just delete random answers, you can give a comment. I can report you for doing that.

So since it burns at 1.3 per hour. Notice that since it gets removed per hour. so it would be 1.3t so it multiplies per hour. Then we need to subtract. Thats because it lowers the length of the candle. So we get the original length - 17 and get the function

f(t) = 17-1.3t

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3 years ago
What is m &lt; 8 if m &lt; 4 = 50° ? <br> A) 50°<br> B) 180° <br> C) 70°<br> D) 40°
icang [17]

Answer:


Step-by-step explanation:


7 0
3 years ago
Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie
melamori03 [73]

Answer:

The complete solution is

\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

y = e^{mx}

Differentiating with respect to x

y'= me^{mx}

Again differentiating with respect to x

y''= m ^2 e^{mx}

Putting the value of y, y' and y'' in left side of the differential equation

3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0

\Rightarrow 3m^2-8m-3=0

The auxiliary equation is

3m^2-8m-3=0

\Rightarrow 3m^2 -9m+m-3m=0

\Rightarrow 3m(m-3)+1(m-3)=0

\Rightarrow (3m+1)(m-3)=0

\Rightarrow m = 3, -\frac13

The complementary function is

y= Ae^{3x}+Be^{-\frac13 x}

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)    

For particular integral

y_p=\frac 1{(3D+1)(D-3)} .4

    =4.\frac 1{(3D+1)(D-3)} .e^{0.x}    [since e^{0.x}=1]

   =4\frac{1}{(3.0+1)(0-3)}      [ replace D by 0 , since L(0)≠0]

   =-\frac43

The complete solution is

y= C.F+P.I

\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43

4 0
3 years ago
Please help me out !
Ahat [919]

Answer:

a) -9/-10 (4th)

b) -3/5 (4th)

3 0
3 years ago
Read 2 more answers
Determine the exact solution to the following in radians.
Sloan [31]
3sinx+1=sinx
2sinx+1=0
2sinx=-1
sinx=-1/2
x=sin^-1 (1/2) = 30 = \pi/6 (when finding the inverse, always take the positive value, ignore the negative sign)
x is therefore negative in 3rd and 4th quadrant
Therefore values of x are:
180+30=210 = 7\pi/6
360-3=330 = 11\pi/6
3 0
3 years ago
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