Pls help me calculate the total area of compound shapes?!?!?

Mathematics

1 answer:

Elza [17]2 years ago

4 0

Answer:

Left: 42ft^2

Right: 21ft^2

Step-by-step explanation:

Its the same question as last time.

Left: (3*10) + (2*6) = 42

Right: (3*5) + (2*3) = 21

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.........help...............

stealth61 [152]

Answer:

1. X axis, 8, 3

2. Y axis, 4,-9

Step-by-step explanation:

The rule of reflections that the place opposite of the axis is negative so:

The rule for x-axis reflection is (x,-y)

The rule for y-axis is (-x,y)

For the first one, x has remained the same, so that means it’s a x-axis reflection.

So change -3 to 3

Same for the next one.

-9 is not changed so that means it’s a y-axis reflection.

And the point is 4,-9

7 0

3 years ago

Read 2 more answers

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$