1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sergeu [11.5K]
3 years ago
13

What is the answer for the picture #26

Mathematics
2 answers:
Lesechka [4]3 years ago
6 0

Oh you're so close !

Just look again at #22, right above it. 
Your answer to #22 is correct.
Think hard again about #22.
You'll see how it can help you solve #26, completely on your own.


viktelen [127]3 years ago
3 0

the answer is 1/13 ². Because if you divide 1/169 and 1/13, then you get 1/13. With that being said, if you multiply 1/13 and 1/13, then you get 1/169. And of course the symbol ( ² ) means squared so you multiply that number he (² ) is over twice. So like 3², 3*3=9.


Helpful???

You might be interested in
Find the x and y intercepts for the following. X= -(y-1) ^2-2
Vanyuwa [196]

Answer:

x intercepts: (-3, 0)

y intercepts: (None)

Step-by-step explanation:

6 0
2 years ago
write an equation to represent the relationship "a number decreased by negative 7 is the same thing as 48
gavmur [86]
X-7=485267532564256732
5 0
3 years ago
Read 2 more answers
A photoconductor film is manufactured at a nominal thickness of 25 mils. The product engineer wishes to increase the mean speed
AURORKA [14]

Answer:

A 98% confidence interval estimate for the difference in mean speed of the films is [-0.042, 0.222].

Step-by-step explanation:

We are given that Eight samples of each film thickness are manufactured in a pilot production process, and the film speed (in microjoules per square inch) is measured.

For the 25-mil film, the sample data result is: Mean Standard deviation 1.15 0.11 and For the 20-mil film the data yield: Mean Standard deviation 1.06 0.09.

Firstly, the pivotal quantity for finding the confidence interval for the difference in population mean is given by;

                     P.Q.  =  \frac{(\bar X_1 -\bar X_2)-(\mu_1- \mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~  t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean speed for the 25-mil film = 1.15

\bar X_1 = sample mean speed for the 20-mil film = 1.06

s_1 = sample standard deviation for the 25-mil film = 0.11

s_2 = sample standard deviation for the 20-mil film = 0.09

n_1 = sample of 25-mil film = 8

n_2 = sample of 20-mil film = 8

\mu_1 = population mean speed for the 25-mil film

\mu_2 = population mean speed for the 20-mil film

Also,  s_p =\sqrt{\frac{(n_1-1)s_1^{2}+ (n_2-1)s_2^{2}}{n_1+n_2-2} } = \sqrt{\frac{(8-1)\times 0.11^{2}+ (8-1)\times 0.09^{2}}{8+8-2} } = 0.1005

<em>Here for constructing a 98% confidence interval we have used a Two-sample t-test statistics because we don't know about population standard deviations.</em>

<u>So, 98% confidence interval for the difference in population means, (</u>\mu_1-\mu_2<u>) is;</u>

P(-2.624 < t_1_4 < 2.624) = 0.98  {As the critical value of t at 14 degrees of

                                             freedom are -2.624 & 2.624 with P = 1%}  

P(-2.624 < \frac{(\bar X_1 -\bar X_2)-(\mu_1- \mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } } < 2.624) = 0.98

P( -2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } } < 2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } } <  ) = 0.98

P( (\bar X_1-\bar X_2)-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } } < (\mu_1-\mu_2) < (\bar X_1-\bar X_2)+2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } } ) = 0.98

<u>98% confidence interval for</u> (\mu_1-\mu_2) = [ (\bar X_1-\bar X_2)-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } } , (\bar X_1-\bar X_2)+2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } } ]

= [ (1.15-1.06)-2.624 \times {0.1005 \times \sqrt{\frac{1}{8}+\frac{1}{8} } } , (1.15-1.06)+2.624 \times {0.1005 \times \sqrt{\frac{1}{8}+\frac{1}{8} } } ]

 = [-0.042, 0.222]

Therefore, a 98% confidence interval estimate for the difference in mean speed of the films is [-0.042, 0.222].

Since the above interval contains 0; this means that decreasing the thickness of the film doesn't increase the speed of the film.

7 0
2 years ago
The volume of rectangular prism that measures 7 meters long, 9 meters wide, and 6 meters high is 378m^3
Law Incorporation [45]

Answer:

Step-by-step explanation:

True

7 X 9 X 6 = 378

7 0
3 years ago
Read 2 more answers
PLEASE ASAP:What is the product of all positive divisors of 10
xz_007 [3.2K]

The positive divisors of 10 are: 1, 2, 5, and 10 (these are the numbers that are divisible by 10 with a remainder of 0). To find the product, you just multiply them all together: 1 * 2 * 5 * 10 = 100.

7 0
3 years ago
Other questions:
  • The graph of a function g is shown below. Find the following:<br> g(5x) if g(x)=4<br> g(5x)= ???
    12·1 answer
  • Find the solution set for this equation.<br> - m2 11m = 0<br> Separate the two values with a comma
    12·1 answer
  • The measure of angle W is 100°, and the measure of angle Z is 68°
    12·1 answer
  • 10. The product of two binomials is
    6·1 answer
  • I NEED HELP PLZ!!!!!!!!!!<br> 35 POINTS
    14·1 answer
  • There are 25 girls going to Hershey Park for chorus.
    5·1 answer
  • The polygons are similar. Find the value of y
    5·1 answer
  • 3(8 - x) = 7x - 6<br> I need help
    13·2 answers
  • <img src="https://tex.z-dn.net/?f=%5Csf%2012%5Ctimes%2016%2B35" id="TexFormula1" title="\sf 12\times 16+35" alt="\sf 12\times 16
    11·1 answer
  • A passenger train's distance traveled is monitored over time. The results are displayed in this table. Time (h) 1 2 3 4 5 Distan
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!