The total area of the face of the watch to the nearest tenth of a square centimemter is 9.0 cm²
Since an electronics company is designing a watch with a face that is in the shape of a hexagon and two congruent trapezoids attached. The heights of the trapezoids and the apothem of the hexagon measure 2 centimeters each, and the length of the shorter base of each trapezoid is 1.5 centimeters, the radii of the hexagon, and the base of the trapezoid form a triangle of
- height, h = apothem of the hexagon = 2 cm and
- base, b = length of shorter base of trapezoid.
<h3>Area of the triangle</h3>
So, the area of this triangle is A = 1/2bh
= 1/2 × 1. 5 cm × 2 cm
= 1.5 cm × 1 cm
= 1.5 cm²
<h3>Area of the hexagon</h3>
Since there are 6 of such triangles in the hexagon, the area of the hexagon, A' = 6A
= 6 × 1.5 cm²
= 9.0 cm²
So, the total area of the face of the watch to the nearest tenth of a square centimemter is 9.0 cm²
Learn more about area of a hexagon here:
brainly.com/question/369332
The answer is 4, 3/4s are in 3
A. y=-95x+665 y-intercept is 665
B. Ave rate of change is -95
C. y=0 so x=7 Domain is [0,7]
