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stealth61 [152]
3 years ago
6

Help me please!!!!!!!!!!!

Mathematics
2 answers:
ch4aika [34]3 years ago
7 0
The type of transformation is scaling. the fourt types r translation, rotation, reflection, and scaling. this one get bigger so its scaling
BARSIC [14]3 years ago
6 0
The answer is dilation
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HELP PLS ASAP<br><br><br><br> -5 = 5/12a pls evaluate
Setler79 [48]

Answer:

a = -12

Remember that when a variable is times with a number, you <u>divide</u> the number on both sides.

When a variable is divided by a number, you <u>multiply</u> the number on both sides.

Hope this helps you. Thank you !!

6 0
3 years ago
How you do these problems
nevsk [136]
So basically, think of a ratio as a fraction for these problems. You see the 2 numbers and you put the first one as the numerator and the second as your denominator. For example:

5 to 10

We would change this into:

\frac{5}{10}

Because the problem says to simplify, we can divide both sides by 5 and simplify it into:

\frac{1}{2}

If the problem says 5:10 instead of "5 to 10" it's the same problem just with different wording. If the numbers are labeled, the you can write the labels next to the number it corresponds with.

If you have any questions, feel free to ask down in the comments, I'll be happy to work with you!
6 0
3 years ago
Read 2 more answers
What is the surface area and volume ?
Ugo [173]
The surface area is 1000 and the volume is 49
7 0
3 years ago
Solve for x 3/4×+5/4=4×​
Effectus [21]

Answer:

x = \frac{5}{13}

Step-by-step explanation:

Given

\frac{3}{4} x + \frac{5}{4} = 4x

Multiply through by 4 to clear the fractions

3x + 5 = 16x ( subtract 16x from both sides )

- 13x + 5 = 0 ( subtract 5 from both sides )

- 13x = - 5 ( divide both sides by - 13 )

x = \frac{-5}{-13} = \frac{5}{13}

6 0
3 years ago
Read 2 more answers
Based on probability and if it is appropriate for a decision to be left up to chance, choose every situation that is both statis
svet-max [94.6K]

The situations that are both statistically fair and morally fair are Situation 2, Situation 3 and Situation 5

<h3>How to categorize the situations?</h3>

For a situation to be fair, the probability of every outcome must be equal.

We can now analyze each option using the above highlight

<u>Situation 1</u>

  • Alphabets = 26
  • Probability of vowel = 5/26
  • Probability of consonant = 21/26

The probabilities of vowels and consonant are not equal.

Hence, this situation is not fair

<u>Situation 2</u>

People = 4

P(Each) = 1/4

The probability of each participant is equal in the above scenario i.e. 1/4

Hence, this situation is fair

<u>Situation 3</u>

  • People = 5
  • P(Each) = 1/5

The probability of each cousin is equal in the above scenario i.e. 1/5

Hence, this situation is fair

<u></u>

<u>Situation 4</u>

  • Numbers = 5 i.e. 2 to 6
  • P(Prime) = 3/5
  • P(Composite) = 4/6

The probabilities of prime and composite numbers are not equal.

Hence, this situation is not fair

<u>Situation 5</u>

  • Roommates = 5
  • Cards = 5
  • Aces = 4
  • P(Each) = 1/5

All probabilities are equal in the above scenario i.e. 1/5

Hence, this situation is fair

Read more about probability at:

brainly.com/question/251701

#SPJ1

4 0
3 years ago
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