Which of the following is NOT a reason fitness testing is useful in schools?

A child’s wading pool has a diameter of 5 feet and a height of 2 feet. How much water would it take to fill the pool?

Svetradugi [14.3K]

Answer:

12.5π or ≈39.27

Step-by-step explanation:

The formula for finding the volume is V=πr^2*d (where h is the height and r is the radius).

Plug in the values: V=π(2.5)^2*2 (Diameter=2*Radius)

Solve: V=6.25π*2

V=12.5π

V≈39.27

3 0

2 years ago

the inn has ten rooms. 1/2 of the rooms are reserved for friday. the rest are vacant. If 2 more rooms are reserved for friday, w

Ganezh [65]

7 total rooms will be occupied on Friday.

7 0

3 years ago

Read 2 more answers

a culture started with 1000 bacteria. after 2 hours it grew to 1200 bacteria. predict how many bacteria will be present after 13

lesya692 [45]

The answer is 2300 because the climbing rate is 100 bacteria per hour. so times 100 and 13 and u get 1300 and u have to add that to the a 1000

6 0

2 years ago

Mustafa’s soccer team is planning a school dance as a fundraiser. The DJ charges $200 and decorations cost $100. The team decide

NemiM [27]

Answer:

360 students

Step-by-step explanation:

take the 1,500 dollars needed for profit and add the other variables (100+200),and the total would be 1,800. take that 1,800 and divide that by 5.

4 0

3 years ago

Read 2 more answers

What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

3 years ago