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nika2105 [10]
3 years ago
10

Jenn buys a pair of jeans for $21.99. Her friend Karen spends $6.50 more for the same pair of jeans. Vicki paid the same price a

s Karen for the jeans but bought 2 pairs. How much did Vicki spend?
Mathematics
1 answer:
UNO [17]3 years ago
3 0

Answer:

13.00

6.50 times 2 =13.00

Step-by-step explanation:

You might be interested in
Find the 10th term of the sequence if the explicit function/formula is f(n)=100+10n
Nutka1998 [239]

Answer:

The 10th term of the sequence is 200.

Step-by-step explanation:

Given that,

The sequence is as follows :

f(n)=100+10n

We need to find 10th term of the sequence.

Put n = 10 in the given expression.

f(10)=100+10(10)

= 100 + 100

= 200

Hence, the 10th term of the sequence is 200.

8 0
3 years ago
Use the domain and range of each of the following relations to determine which is a function.
Setler79 [48]

Answer:

A) Not a function

B) Function

C) Function

D) Not a function

Step-by-step explanation:

If the relation has two of the same x-values (that equal different y-values), it is not a function. In other words, if each input value leads to only one output value, classify the relation as a function.

{<u>(-4,3)</u>, (-2,-1), <u>(-4,8)</u>}  = Not a function

{-4, 3), (-2.-1), (-7, 8)}  = Function

{-4,-2,-7, 7} = Function (I think?)

{-4,3). <u>(-2, -1)</u>. <u>(-2, -8)</u>, (-7,8)}= Not a function

4 0
3 years ago
For problems 3 and 4, find the missing side of the triangle. Leave answers in simplest radical form.
maria [59]

Answer: 3. 4\sqrt{13}            4. \sqrt{225}    

Step-by-step explanation:

8^2 + 12^3 = c^2

64 + 144 = c^2

208 = c^2

√208

4\sqrt{13}

The final answer is the square root of 208

8^2 + b^2 = 17^2

64 + b^2 = 289

-64               64

   b^2 = 225

\sqrt{225}

 

7 0
3 years ago
1) Solve the word problem for the portion, rate, or base.
zhenek [66]

Answer:

1) 0.6% of the production is defective.

2) Ana will owe $570.

Step-by-step explanation:

Both questions here are percentage problems

Percentage problems can be explained as a rule of three problem

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.

Percentage problems have a direct relationship between the measures.

1) The problem states that a quality control process finds 46.8 defects for every 7,800 units of production. And asks what percent of the production is defective? We have to answers how many defects are there for 100 units of production. So:

46.8 defects - 7,800 units

x defects - 100 units

7,800x = 4680

x = \frac{4680}{7800}

x = 0.6

0.6% of the production is defective.

2) The problem states that the medical insurance policy requires Ana to pay the first $100 of her hospital expense. The insurance company will then pay 90% of the remaining expense. The total bill is expected to be about $4,800.

Ana has to pay:

P = P1 + P2

-P1 :The first $100

-P2: 10% of the remaining expense. The remaining expense is $4,800-$100 = $4,700. Ana has to pay 10% of this. So

4700 - 100%

P2 - 10%

100P2 = 47000

P2 = \frac{47000}{100}

P2 = $470

Ana will owe P = P1 + P2 = $100 + $470 = $570.

8 0
3 years ago
Brandon is on one side of a river that is 50 m wide and wants to reach a point 300 m downstream on the opposite side as quickly
AlexFokin [52]
Let P be Brandon's starting point and Q be the point directly across the river from P. 
<span>Now let R be the point where Brandon swims to on the opposite shore, and let </span>
<span>QR = x. Then he will swim a distance of sqrt(50^2 + x^2) meters and then run </span>
<span>a distance of (300 - x) meters. Since time = distance/speed, the time of travel T is </span>

<span>T = (1/2)*sqrt(2500 + x^2) + (1/6)*(300 - x). Now differentiate with respect to x: </span>

<span>dT/dx = (1/4)*(2500 + x^2)^(-1/2) *(2x) - (1/6). Now to find the critical points set </span>
<span>dT/dx = 0, which will be the case when </span>

<span>(x/2) / sqrt(2500 + x^2) = 1/6 ----> </span>

<span>3x = sqrt(2500 + x^2) ----> </span>

<span>9x^2 = 2500 + x^2 ----> 8x^2 = 2500 ---> x^2 = 625/2 ---> x = (25/2)*sqrt(2) m, </span>

<span>which is about 17.7 m downstream from Q. </span>

<span>Now d/dx(dT/dx) = 1250/(2500 + x^2) > 0 for x = 17.7, so by the second derivative </span>
<span>test the time of travel, T, is minimized at x = (25/2)*sqrt(2) m. So to find the </span>
<span>minimum travel time just plug this value of x into to equation for T: </span>

<span>T(x) = (1/2)*sqrt(2500 + x^2) + (1/6)*(300 - x) ----> </span>

<span>T((25/2)*sqrt(2)) = (1/2)*(sqrt(2500 + (625/2)) + (1/6)*(300 - (25/2)*sqrt(2)) = 73.57 s.</span><span>
</span><span>
</span><span>
</span><span>
</span><span>mind blown</span>
8 0
3 years ago
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