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2 years ago

Encuentra la velocidad promedio de un móvil que durante su recorrido hacia el Norte tuvo las siguientes velocidades.

Mathematics

1 answer:

yan [13]2 years ago

5 0

The mean or average speed of a mobile moving north is: Vprom= 20.575 m/sec

The average speed of a series of given speed values is calculated by summing each of the speeds and then dividing by the number of speeds , as follows:

Speeds:

V1=18.5m/s

V2=22m/s

V3=20.3m/s

V4=21.5m/s

V avg =?

Average V = ( V1+V2+V3 +V4)/4

Vavg = (18.5m/s + 22m/s +20.3m/s + 21.5m/s)/4

Vavg = 20.575nm/sec

To consult visit: brainly.com/question/11100327

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A 9-kg of mangoes for 12$_____per kg

enot [183]

If 9kg costs 12$, then a single kg costs around 1.3$

This is done with a simple proportion

9 : 12 = 1 : X
x = 12/9
x = 1.33

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3 years ago

If f is the function defined by f(x) = 3x^5 - 5x^4, what are all the x coordinates of points of inflection for the graph of f?

gregori [183]

Answer:

D: 0 and 1

Step-by-step explanation:

Function is defined by;

f(x) = 3x^(5) - 5x⁴

Now, an inflection point will be a point on the graph where the inflection or concavity changes.

Thus, let's find the derivatives until we get there;

f'(x) = 15x⁴ - 20x³

f''(x) = 60x³ - 60x²

So factorizing gives;

f''(x) = 60x²(x - 1)

At f''(x) = 0, we have; x = 0 or x = 1

Thus, the x coordinates of points of inflection are 0 & 1

4 0

3 years ago

A coin is flipped eight times where each flip comes up either heads or tails. How many possible outcomes a) are there in total?

attashe74 [19]

Answer:

There are 256 ways in total.

There are 56 possible outcomes contain exactly three heads.

The possible outcomes contain at least three heads is 219.

The possible outcomes contain the same number of heads and tails are 70.

Step-by-step explanation:

Consider the provided information.

A coin is flipped eight times where each flip comes up either heads or tails.

Part (a) How many possible outcomes are there in total?

Each time we flip a coin it comes up either heads or tail.

Therefore the total number of ways are:

$2\times 2\times 2\times 2\times 2\times 2\times 2\times 2=2^8=256$

Hence, there are 256 ways in total.

Part (b) contain exactly three heads?

We want exactly 3 heads, therefore,

n=8 and r=3

According to the definition of combination: $\binom{n}{r}=\frac{n!}{r!(n-r)!}$

$\binom{8}{3}=\frac{8!}{3!(5)!}=56$

Hence, there are 56 possible outcomes contain exactly three heads.

Part (c) contain at least three heads?

For 3 heads: $\binom{8}{3}=\frac{8!}{3!(5)!}=56$

For 4 heads: $\binom{8}{4}=\frac{8!}{4!(4)!}=70$

For 5 heads: $\binom{8}{5}=\frac{8!}{5!(3)!}=56$

For 6 heads: $\binom{8}{6}=\frac{8!}{6!(2)!}=28$

For 7 heads: $\binom{8}{7}=\frac{8!}{7!(1)!}=8$

For 8 heads: $\binom{8}{8}=1$

Now add them as shown:

56+70+56+28+8+1=219

Hence, the possible outcomes contain at least three heads is 219.

Part (d) contain the same number of heads and tails?

Same number of heads and tails means that the value of r=4.

Therefore,

$\binom{8}{4}=\frac{8!}{4!(4)!}=70$

Hence, the possible outcomes contain the same number of heads and tails are 70.

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kumpel [21]

The missing angle is 40°

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4 years ago

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