substitute the ordered pair (2, 3 ) into the 2 equations
(3 × 2 ) + (4 × 3 ) = 6 + 12 = 18 → True
(2 × 2 ) - (2 × 3 ) = 4 - 6 = - 2 → False
Hence the ordered pair (2, 3 ) is not a solution to the system of linear equations.
When (2, 3 ) is substituted into the first equation, the equation is true.
When (2, 3 ) is substituted into the second equation, the equation is false.
Answer:
a little bit of a function of the cabinet and the cockroaches and zig and sharko and oggy and the cockroaches and zig and sharko and oggy and the cockroaches and zig and sharko and oggy and the cockroaches and zig and sharko and oggy and the cockroaches and zig and sharko and oggy and the cockroaches and zig and sharko and oggy and the cockroaches and zig and sharko and oggy and
Given:
bake sale at least $300
price of each pie is $6.00
let the number of pies be represented by x.
Write the inequality:
6x <u>></u> 300
Solve the inequality:
6x <u>></u> 300
<u>÷6 ÷6</u>
x <u>></u> 50
Graph the inequality.
y = 6x
x is the number of pies sold; x at least 50 and gradually increases.
y is the total sales
The parent. function shifted up by 6 units to produce x + 1 and to the left by 9 units
<h3>What is translation?</h3>
This is a way of changing the position of an object on an xy-plane.
Given the parent function expressed as y = (x – 5)^2 + 7
From the resulting image after translation, we can see that the parent. function shifted up by 6 units to produce x + 1 and to the left by 9 units
Learn more on translation here; brainly.com/question/12861087
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Answer:
2
Step-by-step explanation:
Given the data : 29, 2, 28, 30, 26, 31
Outlier ;
Lower :Q1 - (1.5 * IQR)
Upper : Q3 + (1.5 * IQR)
Q1 = Lower quartile ; Q3 = upper quartile ; IQR = Interquartile range
Using calculator :
Q1 = 26
Q3 = 30
IQR = (Q3 - Q1) = 30 - 26 = 4
Lower : 26 - (1.5 * 4) = 20
Upper : 30 + (1.5 * 4) = 36
Hence, the number in the given data which falls outside the range is 2
