The answer is 11/36
2/12 chance of rolling fours
because there are 2 sides containing a four on both dice combined and 12 sides in total.
Doubles mean you have to roll the same number simultaneously so let’s say we want to calculate the probability for double ones: then it’s 1/6 on the first dice for a one, and 1/6 on the second dice to land on a one as well.
I personally like to imagine a box like this:
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If you have one dice then it’s just a random segment on one of the lines. If you want the specific result from two dice then you want two specific segments which is also the 1 specific tile out of 36 (6 width times 6 height). So you multiply.
1/6 * 1/6 = 1/36 chance to roll double of ones
And 1/36 chance to roll double twos, threes, fours, fives, and sixes. But we don’t count the double fours because any four will do. So:
1/36 * 5 = 5/36
So for the probability of either doubles or containing a four is the probability of doubles of either number plus the probability of either dice being a four:
5/36 + 2/12 =
5/36 + 6/36 =
11/36
Answer:
(-4,22)
Step-by-step explanation:
is the right answer
Answer:
C
Step-by-step explanation:
Dividend policy (hypothesis) of firms as stated by Musa (2009) is a cultural phenomenon that changes continuously according to environment and time, hence it is necessary to continuously modify dividend behavioural models to capture those factors that are peculiar to a particular period and environment, as well as changes in tax.
Hope this helps
Answer:
Step-by-step explanation:
3×1405 and $.65
4 tenths and 2 hundredths is written .42
2 tenths and 4 hundreds is written .24
.42 is greater than .24
.42 > .24
Hope this helps.
