Answer:
The variable, y is 11°
Step-by-step explanation:
The given parameters are;
in triangle ΔABC;
in triangle ΔFGH;
Segment
= 14
Segment
= 14
Segment
= 27
Segment
= 19
Segment
= 19
Segment
= 2·y + 5
∡A = 32°
∡G = 32°
∡A = ∠BAC which is the angle formed by segments
= 14 and
= 19
Therefore, segment
= 27, is the segment opposite to ∡A = 32°
Similarly, ∡G = ∠FGH which is the angle formed by segments
= 14 and
= 19
Therefore, segment
= 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;
≅
by Congruent Parts of Congruent Triangles are Congruent (CPCTC)
∴
=
= 27° y definition of congruency
= 2·y + 5 = 27° by transitive property
∴ 2·y + 5 = 27°
2·y = 27° - 5° = 22°
y = 22°/2 = 11°
The variable, y = 11°
Answer:
I couldn't find questions.
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26x3=78
78-x=72
x=6
She needs to buy at least 6 more to have enough for 26 students
How many times does 12 go into 60?
5 times.
What is 100/5?
20
So, 20%.
You could also just divide 12/60 then get .2 and then realize that it is the same as .20 and that is the same as 20%.
F(x) = 3x - 2
f(8) = 3(8) - 2
f(8) = 24 - 2
f(8) = 22
f(-5) = 3(-5) - 2
f(-5) = -15 - 2
f(-5) = -17
f(8) - f(-5) = 22 - (-17)
f(8) - f(-5) = 39
Hope this helped! Good luck! :)