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3 years ago

Write at least 2 numerical expressions for each written phrase below. Then, solve.

Mathematics

1 answer:

zloy xaker [14]3 years ago

7 0

Answer:

a. $\frac{3}{5}(7)\text{ or }\frac{3\times 7}{5}$

b. $\frac{1}{6}(4\times 8)\text{ or }\frac{4\times 8}{6}$

Step-by-step explanation:

In numerical expressions we write numbers with the mathematical symbols ( i.e. '+', '-' etc )

a. Given phrase,

Three fifths of seven,

$\frac{3}{5}(7)$

$=\frac{3\times 7}{5}$

$=\frac{21}{5}$

$=4\frac{1}{5}$

b. One sixth the product of four and eight,

$\frac{1}{6}(4\times 8)$

$=\frac{4\times 8}{6}$

$=\frac{32}{6}$

$=5\frac{1}{3}$

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Vinvika [58]

Answer:

Model A=30, Model B: 20, Model C: 45

Step-by-step explanation:

Let x be the amount of type A mp3 produced, and the amount of model B mp3's produced and z the amount of model C mp3 produced.

Since in total there are 303 hours for electronics work, then:

$3.2x+5.4y+2.2z=303$

Since in total there are 393 hours for assembly, then:

$2.8x+2.4y+5.8z=393$

Since in total there are 416 hours for quality assurance, then:

$4.4x+3.4y+4.8z=416$

Then, the linear system associated to the problem is

$3.2x+5.4y+2.2z=303\\2.8x+2.4y+5.8z=393\\4.4x+3.4y+4.8z=416$

with coefficient matrix $A=\left[\begin{array}{ccc}3.2&5.4&2.2\\2.8&2.4&5.8\\4.4&3.4&4.8\end{array}\right]$ and vector of constant terms $b=\left[\begin{array}{ccc}303\\393\\416\end{array}\right]$

Since the determinant of A is equal to 36.704 then A is invertible.

Then for solve the system $Ax=b$ , is enough find the inverse of A and operate

$Ax=b\\A^{-1}Ax=A^{-1}b\\x=A^{-1}b$

Using Octave we obtain that

$A^{-1}=\left[\begin{array}{ccc}-0.22&-0.50 &0.71\\0.33&0.15&-0.34\\-0.028& 0.35&-0.20\end{array}\right]$

Then

$x=A^{-1}b=\left[\begin{array}{ccc}30\\20\\45\end{array}\right]$

This means that 30 mp3's of model A, 20 of model B and 45 of model C must be produced

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3 years ago

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Answer:

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MA_775_DIABLO [31]

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3 years ago

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