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Anna11 [10]
2 years ago
15

3. Which of the following is an exponential function?

Mathematics
1 answer:
lukranit [14]2 years ago
4 0

Answer:

B is correct I hope this helps.

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The base for patio umbrella is 12 inches in diameter. In terms of π, what's the area of the base?
marin [14]
Dont put C its D 36 pi in ^2
3 0
3 years ago
-2 (2x + 11) = 5x + 14
amid [387]

Answer:

x=-4

Step-by-step explanation:

First, write the expression and distribute.

-2(2x+11)=5x+14

-4x-22=5x+14

Add one of the variables to the other side (it makes solving a lot easier). I'll add 4x to both sides because it won't result in a negative x.

-4x-22=5x+14

<u>+4x      +4x</u>

-22=9x+14

Now, subtract 14 on both sides.

-22=9x+14

<u>-14        -14</u>

-36=9x

Divide both sides by 9.

-36=9x

<u>/9   /9</u>

-4=x  or  x=-4 (they both mean the same thing)

Have a wonderful day! I hope this helped :3

3 0
3 years ago
As an estimation we are told £3 is €4.<br> Convert £72 to euros.
Luden [163]

(72×4)÷3

Please solve this

Any answer you get is the Answer

4 0
3 years ago
Read 2 more answers
Can someone please answer the problem? Can someone also tell me what are supplementary angles?
skelet666 [1.2K]
Supplementary angles are angles that add up to 180 degrees

Answer = 180 - 142 = 38 degrees
5 0
4 years ago
Read 2 more answers
What are the zeros of the quadratic function f(x) = 6x ^ 2 - 24x + 1 ?
ZanzabumX [31]

Answer:

x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}

Step-by-step explanation:

Let's use the quadratic formula, which states that for a quadratic of the form ax² + bc + c, the zeroes are: x=\frac{-b+\sqrt{b^2-4ac} }{2a} or x=\frac{-b-\sqrt{b^2-4ac} }{2a}.

Here, a = 6, b = -24, and c = 1. Plug these in:

x=\frac{-b+\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)+\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24+\sqrt{552} }{12}=\frac{24+2\sqrt{138} }{12} =\frac{12+\sqrt{138} }{6}

AND

x=\frac{-b-\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)-\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24-\sqrt{552} }{12}=\frac{24-2\sqrt{138} }{12} =\frac{12-\sqrt{138} }{6}

Thus, the zeroes are: x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}.

3 0
3 years ago
Read 2 more answers
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