Question

Question: How many small dogs are signed up to compete in the dog show?

Answer 1

Answer:

36

Step-by-step explanation:

cuz there are 49 dogs and 36 more smaller dogs that sighed up and it asks how many dogs are sighed up to compete

Answer 2

Answer:

$S=42\frac{1}{2}$ small dogs

Step-by-step explanation:

Let $L$ be the number of large dogs and $S$ be the number of small dogs.

Since it is given that the toal number of dogs that signed up is 49, this makes our first equation $L+S=49$.

Also, there are 36 more small dogs than large dogs that signed up to compete, so this makes our second equation $S=L+36$.

Since the value of $S$ is already solved in our second equation, we can plug it into the first equation and solve for $L$:

$L+S=49$

$L+(L+36)=49$

$L+L+36=49$

$2L+36=49$

$2L=13$

$L=\frac{13}{2}$

$L=6\frac{1}{2}$

Now plug the value of $L$ into either equation and solve for $S$:

$S=L+36$

$S=\frac{13}{2}+36$

$S=\frac{85}{2}$

$S=42\frac{1}{2}$

Even though the answer isn't realistic, it's still correct.