Question

Oscar was not safeguarding his personal identification and chose a two-digit PIN for his debit card using the numbers 0 - 9. Without using the same number twice, how many
different identification numbers are possible?

Answer 1

Answer:

90

Step-by-step explanation:

Each number can be paired up with 10 other numbers.

Ex: 0 can be paired with: 0123456789.

Since there are 10 numbers, we multiply 10 by 10 to get 100.

Now, because you can't use the same number twice, we subtract 10 from 100 because there are 10 numbers that can match with themselves.

100 - 10 = 90

Answer 2

There are 90 different identification numbers possible.

What are the permutation and combination?

In terms of mathematical concepts, “permutation” and “combination” are related to each other.

The combination is the counting of selections that we make from n objects.

Oscar was not safeguarding his personal identification and chose a two-digit PIN for his debit card using the numbers 0 - 9.

There are 10 possible values for each digit of the PIN (namely: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9), so there are;

10 × 10 = 100 total possible PINs.

Now, because you can't use the same number twice, we subtract 10 from 100 because there are 10 numbers that can match themselves.

100 -10 =90

Hence, there are 90 different identification numbers possible.

Learn more about combination here;

brainly.com/question/24138361

#SPJ2