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topjm [15]
3 years ago
5

Factor the GCF: −12x3y5 − 9x2y2 + 12xy33xy2(−4x2y3 − 3x + 4y)−3xy2(4x2y3 − 3x + 4y)−3(4x3y5 + 3x2y2 − 4xy3)−3xy2(4x2y3 + 3x − 4y

)
Mathematics
1 answer:
butalik [34]3 years ago
4 0

Answer:

3xy^2(-4x^2y^3-3x+4y)

Step-by-step explanation:

The given expression is

-12x^3y^5-9x^2y^2+12xy^3

To find the greatest common factor; we find the prime factorization of each term in the expression.

-12x^3y^5=-2^2\times3\timesx^3\times y^5

-9x^2y^2=-3^2\times x^3 \times y^2

12xy^3=2^2\times 3\times x\times y^3

The greatest common factor is the product of the least powers of the common factors.

GCF=3xy^2

We factor the GCF to obtain;

-12x^3y^5-9x^2y^2+12xy^3=3xy^2(-4x^2y^3-3x+4y)

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m<4=104 degrees

Step-by-step explanation:

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Answer:

5x + 2x.....combine like terms..... = 7x

5x + 2x....subbing in 1                               7x - 1....subbing in 1

5(1) + 2(1) = 5 + 2 = 7                               7(1) - 1 = 7 - 1 = 6

5x + 2x...subbing in 2                                 7x - 1...subbing in 2

5(2) + 2(2) = 10 + 4 = 14                            7(2) - 1 = 14 - 1 = 13

5x + 2x...subbing in 3                                 7x - 1...subbing in 3

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5x + 2x...subbing in 4                                 7x - 1....subbing in 4

5(4) + 2(4) = 20 + 8 = 28                            7(4) - 1 = 28 - 1 = 27

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5x + 2x result values are 1 more then 7x - 1 result values

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Step-by-step explanation:

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The given statement is:
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2) If the last two digits of an integer are zeros, it is divisible by 100.

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