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Stolb23 [73]
1 year ago
13

. An ant is standing at the center of a perfectly circular plate. If the ant crawled in a straight line, he would have to crawl

6 inches to reach the edge of the plate. How many inches would he crawl if he crawled a full circle around the edge of the plate?
Mathematics
1 answer:
trapecia [35]1 year ago
6 0

The size around the circular edge of the plate is 37.68 inches

<h3>How to find the circumference of a circle?</h3>

The circumference of a circle can be solved as follows:

The ant is standing at the centre of a perfectly circular plate and it walks to the edge of the plate .

The centre of the plate to the edges is 6 inches. Therefore, the radius of the circular plate is 6 inches.

Hence, the distance around the edge of the plate is the circumference of the plate.

Therefore,

circumference of the circular plate = 2πr

circumference of the circular plate = 2 × π × 6

circumference of the circular plate = 12π

circumference of the circular plate = 12 × 3.14

circumference of the circular plate = 37.68 inches

learn more on circle here: brainly.com/question/9330354

#SPJ1

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Answer:

4x² -4xy -4y -4

Step-by-step explanation:

\boxed{ {a}^{2}  -  {b}^{2}  = (a + b)(a - b)}

In this case, a= 2x -y and b= y +2.

(2x -y)² -(y +2)²

= (2x -y +y +2)[2x -y -(y +2)]

= (2x +2)(2x -y -y -2)

= (2x +2)(2x -2y -2)

= 2x(2x) +2x(-2y) +2x(-2) +2(2x) +2(-2y) +2(-2) <em>(expand)</em>

= 4x² -4xy -4x +4x -4y -4

= 4x² -4xy -4y -4

Alternatively, start by expanding the brackets.

\boxed{(a - b)^{2}  =  {a}^{2} - 2ab \:  +  {b}^{2}  }

\boxed{(a + b)^{2}  =  {a}^{2}  + 2ab \:  +  {b}^{2} }

(2x -y)² -(y +2)²

= 4x² -4xy +y² -(y² +4y +4)

= 4x² -4xy +y² -y² -4y -4 <em>(</em><em>expand</em><em>)</em>

= 4x² -4xy -4y -4 <em>(</em><em>simplify</em><em>)</em>

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Step-by-step explanation:

\small\mathfrak\red{here \: is \: your \: solution...} \\  \\ \small\mathcal\purple{volume \: of \: hemisphere \:  = (2 \div 3)\pi \: r ^{3 \: } .} \\  \\ \small\mathfrak\purple{radius \: of \: hemisphere \:  = 6 \: cm.} \\  \\ \small\mathfrak\purple{volume \: of \: hemisphere \:  = (2 \div 3)(22 \div7 ) \times 6 {}^{3} .} \\  \\ \small\mathfrak\purple{volume \:  = 452.16 \: cm {}^{3} .} \\  \\ \huge\mathfrak\pink{hope \: it \: helps.}

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