Answer:
The ratio of the income in 2003 would be $54,300.
Step-by-step explanation:
Given that the yearly income for an individual with an associate degree in 2001 was $53,166 and 2013 was $59,970, we can determine that in 12 years there was a wage increase of $ 6,804 (59,970 - 53,166). Thus, on average, each year there was a salary increase of $ 567 (6,804 / 12). Therefore, given that in 2003 two years had passed since the starting value of $ 53,166, following this reasoning and without inflationary or recessionary changes, this person's salary should have been $ 54,300 (53,166 + 567 x 2).
Answer:
73.4 cm^2
Step-by-step explanation:
The equation is :
πr^2
Substitute the radius in:
π(5)^2
Solve:
Area of full circle = 25π
(Note : leave this answer in terms of 'pi' so it is easier to handle
Next, find the area of the sector
The equation for this is:
(angle/360) x πr^2
Substitute the values in:
(80/360) x π(5)^2
Solve :
Area of sector = (50/9)π
Now, find the area of the triangle:
1/2 absinC
Substitute the values in:
1/2(5)(5) x sin(80) = 12.31009691
Subtract this answer from the area of the sector
Answer = 5.14319607
Subtract this from the area of the whole circle
Answer = 73.39662073
To the nearest tenth, that would be 73.4 cm^2
Mark brainliest pls
Answer: the vide games cost about 6 dollars and the movies cost 3 i think
Step-by-step explanation: divide 40 by 6 then 6 by 2 equals 3 (i hope this helps)
Answer:
A
Step-by-step explanation:
Answer:
Step-by-step explanation:
The solution of a system of linear equations is the point of intersection of their graphs because the intersection represents the only x or y values that will satisfy both/all equations. The graph visually shows that the intersection of these equations is the only spot on the graph that all of the equations have in common. This means that only this spot will satisfy all equations. For example, the intersection may be (0,1); this means that for all equations an x value of 0 will always result in the y value of 1. However, an x or y value that satisfies one equation may not satisfy the others if they do not lead to the desired outcome.
