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Feliz [49]
3 years ago
6

HELP ME PLEASE I APPRECIATE IT

Mathematics
1 answer:
Molodets [167]3 years ago
5 0
1 is m=n/x
2 is 15 rows
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A rectangle has an area of 18 cm², with a perimeter of 18 cm. Find the length and breadth
pashok25 [27]

Answer:

suppose length is x

breadth is y

now,

      x.y=18

      2(x+y)= 18

x= 3

y=6

Step-by-step explanation:

6 0
3 years ago
-2(4x - 4) + x<br> Need help<br> Show work
IgorC [24]

Answer:

Distribute:

=(−2)(4x)+(−2)(−4)+x

=−8x+8+x

Combine Like Terms:

=−8x+8+x

=(−8x+x)+(8)

=−7x+8

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Information on a packet of​ seeds, which may not be a random sample of​ seeds, claims that the germination rate is 94​%. ​What's
Evgesh-ka [11]

Answer:

0.1052

Step-by-step explanation:

Given that proportion of germination in the population is 94% =0.94

p = 0.96

Sample size = 220

Std dev of p = \sqrt{\frac{pq}{n} } \\=0.016

The probability that more than 96​% of the 220 seeds in the packet will​ germinate

= P(p\geq 0.96)\\=P(Z\geq \frac{0.96-0.94}{0.016})\\=P(Z\geq 1.25)\\==1-0.8948\\=0.1052

Assumptions are np and nq >5 and also sample size >220 hence normal

7 0
3 years ago
The dashed triangle is the image of the pre-image solid triangle.
BabaBlast [244]
The scale factor  is 4.
6 0
3 years ago
Read 2 more answers
Can you help me answer this? please​
Leya [2.2K]

Answer: 1859.5 mini bears

Step-by-step explanation:

From the information given in the question,

10 mini bars = 12.1 grams

10 regular bars = 23.1 gram

1 super bear = 2250 grams

To eat enough mini bears to match the super bears, the number that it'll take will be:

Since 10 mini bars = 12.1 grams

1 mini bear = 12.1 grams / 10 = 1.21 gram

Since 1 super bear = 2250 grams, the number of mini bears needed to equate this will be:

= 2250/1.21

= 1859.5 mini bears

5 0
3 years ago
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