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4 years ago

HELP!! ILL GIVE THE BRIANLIEST to whoever ANSWERS CORRECTLY!!

Mathematics

2 answers:

Vesnalui [34]4 years ago

6 0

I got the answer A. 26.65

stich3 [128]4 years ago

3 0

Answer:

Step-by-step explanation:

cuz i said so ahahahahah

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Crystal buys headphones that are on sale with a 40% discount. If crystal pays $24 for the headphones with the discount, what is

olga_2 [115]

$60 I belive is the answer

3 0

3 years ago

Read 2 more answers

Find the value of x. Then find the measure of each labeled angle.<br> (9x - 10)<br> (5x + 38)

omeli [17]

Answer:

x=12 and

(9*12)-10=98

(5*12)+38=98

both angles are = 98

Step-by-step explanation:

do this :

9x - 10 = 5x + 38

( - 5x from both sides)

4x - 10 = 38

(add 10 to both sides)

4x = 38+10

4x=48

(divide by 4)

x=48/4

= 12

substitute into the equations:

(9*12)-10

(5*12)+38

3 0

3 years ago

Select the number that is a multiple of two a 31 b 57 c 85 d 98

Lynna [10]

Answer:

Step-by-step explanation:

option d..............

6 0

3 years ago

Read 2 more answers

Need help with this please help

elena-14-01-66 [18.8K]

There is 24 avocados in each crate

Divide 8640 and 360 to get 24

Hope this will help you!

7 0

3 years ago

What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?

telo118 [61]

Answer:

$f(x)=-\frac{1}{8}(x-3)^2+3$

Step-by-step explanation:

We want to find the equation of the parabola with a focus of $(3,1)$ and directrix $y=5$ .

Considering the directrix, the quadratic graph must open downwards.

The equation of this parabola is given by the formula,

$(x-h)^2=4p(y-k)$ , where $(h,k)$ is the vertex of the parabola.

The axis of this parabola meets the directrix at $(3,5)$ .

Since the vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix,

$h=\frac{3+3}{2}=3$ and $k=\frac{5+1}{2}=3$ .

The equation of the parabola now becomes,

$(x-3)^2=4p(y-3)$ .

Also $|p|$ is the distance between the vertex and the directrix.

$|p|=2$

This implies that $p=-2\:or\:2$ .

Since the parabola turns downwards,

$p=-2$ .

Our equation now becomes,

$(x-3)^2=4(-2)(y-3)$ .

$(x-3)^2=-8(y-3)$ .

We make y the subject to get,

$y=-\frac{1}{8}(x-3)^2+3)$ .

This is the same as

$f(x)=-\frac{1}{8}(x-3)^2+3)$ .

4 0

3 years ago