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alexandr402 [8]
3 years ago
13

You have learned three ways for solving systems of equations: graphing, substitution and elimination.

Mathematics
1 answer:
ra1l [238]3 years ago
6 0

Answer:

Elimination

Step-by-step explanation:

Graphing takes too long, substitution can sometimes complicate things quickly, therefore I would use elimination as my prime method of solving systems of equations.

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What is the value of f(-1) when f(x)=2x+2? F(-1)=?
igomit [66]

Here is your function:

f(x)=2x+2

You're looking for f(-1). To get your answer, you have to replace all the x's with -1.

Here is your new equation:

f(-1) = 2(-1)+2

Multiply 2 by -1

2 \times -1 = -2

<em>Remember:</em>

MULTIPLYING

  • Positive(+) times negative(-) is equal to negative
  • Positive(+) times positive(+) is equal to positive
  • Negative(-) times negative(-) is equal to positive
  • Negative(-) times positive(+) is equal to negative

DIVIDING

  • Positive(+) divided by positive(+) is equal to positive
  • Positive(+) divided by negative(-) is equal to negative
  • Negative(-) divided by positive(+) is equal to negative
  • Negative(-) divided by negative(-0 is equal to positive

Since you're multiplying a negative number by a positive number, the answer will be negative.

Here is your new equation:

f(-1) = -2+2

Add -2 and 2:

-2+2 = 0

That means your answer is 0

        ↓

f(-1)=0

<em>If you have any questions, feel free to ask in the comments! :)</em>

5 0
3 years ago
Use long division to find the quotient: 7/8.<br><br> I just don´t get it?
Aleonysh [2.5K]

Answer:

0.875

Step-by-step explanation:

you just divide 7 by 8, and you would get 0.875

7/8=0.875

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A boat can travel 315 miles on 63 gallons of gasoline. How much gasoline will it need to go 5 miles?
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\begin{array}{ccll} miles&\stackrel{gasoline}{gallons}\\ \cline{1-2} 315 & 63\\ 5& x \end{array} \implies \cfrac{315}{5}~~=~~\cfrac{63}{x} \\\\\\ 63=\cfrac{63}{x}\implies 63x=63\implies x=\cfrac{63}{63}\implies x=1

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The graph is below.  


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This would be true. The points make up a straight line
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