90
Step-by-step explanation:vkjl
Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.

Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)
10.54 cm^2. You just have to find area of the square then area of the circle. Subtract the area of the circle from the square to get the answer
Answer:
3
Step-by-step explanation:
I gussed but I'm not sure
Answer:
-1, 0, 1, 2
Step-by-step explanation:
-1 + 0 + 1 + 2 = 2