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Tresset [83]
2 years ago
13

If you shift the exponential parent function, f(x) = 2^x , right 2 units, what is the equation of the new function?

Mathematics
2 answers:
anyanavicka [17]2 years ago
7 0

We know the rule for shifting right(x is changed)

  • f(x) —» f(x-a)

So

here

For a =2

  • f(x-2)
  • \sf 2^{x-2}
aev [14]2 years ago
6 0

Answer:

g(x)=2^{x-2}

Step-by-step explanation:

<u>Translations</u>

For a > 0

f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}

f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}

f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}

f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}

Parent function:  f(x)=2^x

Translated 2 units right:  g(x)=f(x-2)=2^{x-2}

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Bennett has 107 photographs to place in the school yearbook. He will put the same number of photos on each of the 13 pages. if h
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How many complex zeros does the polynomial function have?<br> f(x)=−3x^6−2x^4+5x+6
REY [17]

one way would be to factor

I can't factor it so we will have to use Descartes' Rule of Signs which is helpful for finding how many real roots you have


it goes like this:

for a polynomial with real coefients, consider f(x)=-3x^6-2x^4+5x+6.

after arranging the terms in decending order in terms of degree, count how many times the signs of the coeffients change direction and minus 2 from that number until you get to 1 or 0. that will be the number of even roots the function can have

We have (-, -, +, +). the signs changed 1 times, so it has 1 real positive root


to get the negative roots, we evaluate f(-x) and see how many times the root changes

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signs are (-, -, -, +). there was 1 change in sign

so the function has 1 real negative root



a total of 2 real roots


a function of degree n can have at most, n roots


our function is degree 6 so it has 6 roots

if 2 are real, then the others must be complex

6-2=4 so there are 4 complex roots


you can also show that there are only 2 real roots by using a graphing utility to see that there are only 2 real roots

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What grade is this?..

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