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RoseWind [281]
3 years ago
11

The table shows the type of super power students wish they had. Super power Students Flight 888 Super strength 101010 X-ray visi

on 666 Invisibility 121212
Mathematics
1 answer:
pogonyaev3 years ago
3 0

Answer:

the answer is A and B

Step-by-step explanation:

You might be interested in
Find b in triangle TRG. Please help, I'm not sure how to solve for b.
Marina CMI [18]

Answer:

b=4.9

C. is the correct option.

Step-by-step explanation:

In triangle TGN,

Let <RTG be x

cosx= b/h

or, cosx = 2/a

Again,

In triangle TRG,

cosx = b/h

(for bigger right angled triangle)

cosx = a/(4+2)

cosx = a/6

Now

cosx = 2/a = a/6

or, 2/a = a/6

or, 12 = a²

so, a² = 12

Now,

For TRG,

h² = p²+b²

or, 6² = b² + a²(a²=12)

or, 6² = b² + 12

or, 36 = b² + 12

or, 36 -12 = b²

or, b² = 24

or, b = square root 24

so, b = 4.8989

so, b = 4.9

7 0
2 years ago
Noah saw some worms in his garden. He measured the length of each worm.
sergeinik [125]

Answer:

9 worms are longer than 3 inches

Step-by-step explanation:

you can just count how many are in in the rows after 3 and that is your answer

5 0
3 years ago
Find the center and radius of circle and graph it <br><br> <img src="https://tex.z-dn.net/?f=%28x-4%29%5E%7B2%7D%20%2B%28%20y%20
sergeinik [125]

Answer:

centre = (4,-2)

radius = 3

Step-by-step explanation:

The centre-radius form of the circle equation is in the format

(x – h)² + (y – k)² = r²,

with the centre being at the point (h, k) and the radius being "r"

Given in the question an expression which can be write as

<h3> (x – 4)² + (y – (-2))² = 3²</h3>

So, by translating we can say that

centre = (4,-2)

and

radius = 3

 

3 0
3 years ago
What is 5.95 × 106 written in standard form? A. 595,000 B. 59,500 C. 5950 D. 5,950,000
tiny-mole [99]
The answer is option D "<span>5,950,000".

</span>5.95 * 10^6 = &#10;&#10;5 9 5 0 0 0 0/&#10;1 2 3 4 5 6

Which would equal 5,950,000.

Hope this helps!
7 0
3 years ago
Find an equation of the tangent line to the curve at the given point. y = x + tan(x) at (pi, pi)
S_A_V [24]
<span>Differentiating :

y' = 1 + sec^2(x),
</span><span>
cosπ=−1</span><span>

plug in pi = -1 ,for x:

1 + sec^2(pi) = 1 +  (-1)^2 
                      = 2</span>
8 0
3 years ago
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